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Lyrx [107]
3 years ago
8

For an object that travels at a fixed speed along a circular path, the acceleration of the object is

Physics
2 answers:
lidiya [134]3 years ago
8 0
For an object that travels at a fixed speed along a circular path, the acceleration of the object is LARGER IN MAGNITUDE THE SMALLER THE RADIUS OF CIRCLE.
Dmitrij [34]3 years ago
7 0

Answer:

A) larger in magnitude the smaller the radius of the circle.

Explanation:

The acceleration for an object in circular motion is the centripetal acceleration, which points in the direction of the center of the circle. The formula for this acceleration is:

a=\frac{v^2}{r}

where v is the velocity of the object, and r is the radius of the circle.

from this equation we conclude that the acceleration and the radius have an inverse relationship -> this means that the larger the acceleration is, the radius has to be smaller, and vice versa if the acceleration is small, the radius is larger.

The option that describes this relationship is: A) larger in magnitude the smaller the radius of the circle.

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denpristay [2]

Answer:

1 = C

2 = B

Explanation:

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3 years ago
n 38 g rifle bullet traveling at 410 m/s buries itself in a 4.2 kg pendulum hanging on a 2.8 m long string, which makes the pend
Kitty [74]

Answer:

68cm

Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

p_f=p_i\\mv_1+Mv_2=(m+M)v

m: mass of the bullet

M: mass of the pendulum

v1: velocity of the bullet = 410m/s

v2: velocity of the pendulum =0m/s

v: velocity of both bullet ad pendulum joint

By replacing you can find v:

(0.038kg)(410m/s)+0=(0.038kg+4.2kg)v\\\\v=3.67\frac{m}{s}

this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2

g: 9.8/s^2

h: height

By doing h the subject of the equation and replacing you obtain:

(0.038kg+4.2kg)(9.8m/s^2)h=\frac{1}{2}(0.038kg+4.2kg)(3.67m/s)^2\\\\h=0.68m

hence, the heigth is 68cm

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One terminal of a car battery is said to be connected to “ground.” since it is not really connected to the ground, what is meant
GalinKa [24]
This expression means that the negative terminal (-) is connected to the metal chassis or engine, which means that all voltages used for the electrical devices in the car are measured with respect to the car's chassis or engine. 
Today's vehicles have a negative ground system, which means that the vehicle's steel frame or chassis is directly connected to the negative side of the battery via the negative battery cable. 
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4 years ago
If each Coulomb of charge is given 20 Joules of energy, what is the voltage of the battery?
Assoli18 [71]

Answer:

Explanation:

V = J/C

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Option A is the correct answer

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