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3 years ago

For an object that travels at a fixed speed along a circular path, the acceleration of the object is

2 answers:

8 0

For an object that travels at a fixed speed along a circular path, the acceleration of the object is LARGER IN MAGNITUDE THE SMALLER THE RADIUS OF CIRCLE.

Dmitrij [34]3 years ago

7 0

Answer:

A) larger in magnitude the smaller the radius of the circle.

Explanation:

The acceleration for an object in circular motion is the centripetal acceleration, which points in the direction of the center of the circle. The formula for this acceleration is:

$a=\frac{v^2}{r}$

where $v$ is the velocity of the object, and $r$ is the radius of the circle.

from this equation we conclude that the acceleration and the radius have an inverse relationship -> this means that the larger the acceleration is, the radius has to be smaller, and vice versa if the acceleration is small, the radius is larger.

The option that describes this relationship is: A) larger in magnitude the smaller the radius of the circle.

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3 years ago

When the rudder moves to the left the plane will move to the right or left?

mrs_skeptik [129]

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3 years ago

Read 2 more answers

A charged particle is moving perpendicular to a magnetic field in a circle with a radius r. An identical charge particle enters

emmasim [6.3K]

Answer:

<em>The second particle will move through the field with a radius greater that the radius of the first particle</em>

Explanation:

For a charged particle, the force on the particle is given as

$F = \frac{mv^{2} }{r}$

also recall that work is force times the distance traveled

work = F x d

so, the work on the particle = F x d,

where the distance traveled by the particle in one revolution = $2\pi r$

Work on a particle = 2πrF = $2\pi mv^{2}$

This work is proportional to the energy of the particle.

And the work is also proportional to the radius of travel of the particles.

Since the second particle has a bigger speed v, when compared to the speed of the first particle, then, the the second particle has more energy, and thus will move through the field with a radius greater that the radius of the first particle.

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2 years ago

Which one of the following statements is true concerning the magnitude of the electric field at a point in space? It is a measur

IceJOKER [234]

Answer:

It is a measure of the electric force per unit charge on a test charge.

Explanation:

The magnitude of the electric field is defined as the force per charge on the test charge.

Since we define electric field as the force per charge, it will have the units of force divided by the unit of charge. This implies that the SI unit of electric field is given as Newton/Coulomb (N/C).

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2 years ago

9) What will happen to the period of a pendulum if we change the rope of a pendulum with another which is four times with the in

Arturiano [62]

Double

Explanation:

Since the period T of a pendulum is given by

$T = 2\pi \sqrt{\dfrac{l}{g}}$