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3 years ago

For an object that travels at a fixed speed along a circular path, the acceleration of the object is

2 answers:

8 0

For an object that travels at a fixed speed along a circular path, the acceleration of the object is LARGER IN MAGNITUDE THE SMALLER THE RADIUS OF CIRCLE.

Dmitrij [34]3 years ago

7 0

Answer:

A) larger in magnitude the smaller the radius of the circle.

Explanation:

The acceleration for an object in circular motion is the centripetal acceleration, which points in the direction of the center of the circle. The formula for this acceleration is:

$a=\frac{v^2}{r}$

where $v$ is the velocity of the object, and $r$ is the radius of the circle.

from this equation we conclude that the acceleration and the radius have an inverse relationship -> this means that the larger the acceleration is, the radius has to be smaller, and vice versa if the acceleration is small, the radius is larger.

The option that describes this relationship is: A) larger in magnitude the smaller the radius of the circle.

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Which describes what an outside observer at rest would observe about a spaceship that speeds up and approaches the speed of ligh

Art [367]

The outside observer, at rest relative to the spaceship, would see the spaceship
get shorter. and the clocks on the spaceship run slower than they should.

At the same time, the crew of the spaceship, looking back at the observer on
Earth, would see the observer on Earth get shorter, and the observer's clock
run slower than it should.

They would both be measuring what they see correctly.

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3 years ago

Read 2 more answers

Calculate the mass number of an atom with 8 protons, 12 neutrons and 10 electrons

Radda [10]

Answer: 20

Explanation: Mass number is the number of neutrons plus the number of protons. 8 + 12 gives 20.

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3 years ago

Three observers watch a train pull away from a station toward the right of the platform. Observer A is in one of the train’s car

juin [17]

Observer A is moving inside the train

so here observer A will not be able to see the change in position of train as he is standing in the same reference frame

So here as per observer A the train will remain at rest and its not moving at all

Observer B is standing on the platform so here it is a stationary reference frame which is outside the moving body

So here observer B will see the actual motion of train which is moving in forward direction away from the platform

Observer C is inside other train which is moving in opposite direction on parallel track. So as per observer C the train is coming nearer to him at faster speed then the actual speed because they are moving in opposite direction

So the distance between them will decrease at faster rate

Now as per Newton's II law

F = ma

Now if train apply the brakes the net force on it will be opposite to its motion

So we can say

- F = ma

$a = \frac{-F}{m}$

so here acceleration negative will show that train will get slower and its distance with respect to us is now increasing with less rate

It is not affected by the gravity because the gravity will cause the weight of train and this weight is always counterbalanced by normal force on the train

So there is no effect on train motion

5 0

3 years ago

A steel cable has a cross-sectional area 2.54 10-3 m2 and is kept under a tension of 1.01 104 N. The density of steel is 7860 kg

ElenaW [278]

Answer:

The speed is equals to 22.49 m/s

Explanation:

Given Data:

$Area = A=2.54*10^-^3m^2\\Force = F = 1.01*10^4N\\density = p = 7860 kg/m^3$