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Lyrx [107]
3 years ago
8

For an object that travels at a fixed speed along a circular path, the acceleration of the object is

Physics
2 answers:
lidiya [134]3 years ago
8 0
For an object that travels at a fixed speed along a circular path, the acceleration of the object is LARGER IN MAGNITUDE THE SMALLER THE RADIUS OF CIRCLE.
Dmitrij [34]3 years ago
7 0

Answer:

A) larger in magnitude the smaller the radius of the circle.

Explanation:

The acceleration for an object in circular motion is the centripetal acceleration, which points in the direction of the center of the circle. The formula for this acceleration is:

a=\frac{v^2}{r}

where v is the velocity of the object, and r is the radius of the circle.

from this equation we conclude that the acceleration and the radius have an inverse relationship -> this means that the larger the acceleration is, the radius has to be smaller, and vice versa if the acceleration is small, the radius is larger.

The option that describes this relationship is: A) larger in magnitude the smaller the radius of the circle.

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Can kintic friction affect mechanical energy
Nesterboy [21]
Yes. Kinetic energy is a form of mechanical energy and friction will turn that kinetic energy into heat.
3 0
3 years ago
a 100g ice cube at 0 degrees celsius is placed in 650 grams of water at 25 degrees celsius. When the mixture reaches equillibriu
Artyom0805 [142]

Answer:

The latent heat of fusion of water is 334.88 Joules per gram of water.

Explanation:

Let the latent heat of ice be 'x' J/g

1) Thus heat absorbed by 100 gram of ice to get converted into water equals

Q_1=100\times x

2) heat energy required to raise the temperature of water from 0 to 25 degree Celsius equals

Q_2=100\times 4.186\times 11=4604.6Joules

Thus total energy needed equals Q_1+Q_2=100x+4604.6

3) Heat energy released by the decrease in the temperature of water from 25 to 11 degree Celsius is

Q_3=650\times 4.186\times (25-11)\\\\Q_{3}=38092.6Joules

Now by conservation of energy we have

Q_1+Q_2=Q_3\\\\100x+4604.6=38092.6\\\\\therefore x=\frac{38092.6-4604.6}{100}=334.88J/g

6 0
3 years ago
A spring with a spring constant value of 2500 StartFraction N over m EndFraction is compressed 32 cm. A 1.5-kg rock is placed on
Sedaia [141]

Answer:

it's 9m

Explanation:

5 0
3 years ago
Read 2 more answers
A force acts on a body of mass 13 kg initially at rest. The force
PtichkaEL [24]

Answer:

Force that acted on the body was F = 13 N

Explanation:

If once accelerated, the body covers 60 meters in 6 seconds, then its velocity is 60/6 m/s = 10 m/s

When the force was acting (for 10 seconds) the object accelerated from rest (initial velocity vi = 0) to 10 m/s (its final velocity). therefore we can use the kinematic equation for the velocity in an accelerated motion given by:

v_f=v_i+a*t

which in our case becomes;

10\,m/s=0+a*(10\,s)

and we can solve for the acceleration as:

a = 10/10  m/s^2 = 1 m/s^2

Therefore the force acting on the body, based on Newton's 2nd Law expression: F = m * a is:

F = 13 kg * 1 m/s^2 = 13 N

4 0
3 years ago
Name a suitable plece of equipment that could be used to measure the length of the pool.​
Fynjy0 [20]

Answer:

With a tape measure.

Explanation:

We can use a big tape measure, this tape is in the market and we can use the one with the proper length that lets us measure different sections of the total length of the pool.

4 0
3 years ago
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