Answer:
uhh dude what's the question?
Step-by-step explanation:
Answer: 24m-28
Step-by-step explanation:
According to the distributive property ,
, where a, b and c are any arbitrary expressions.
Given expression : 
By using distributive property , we have
![(6m - 7)\cdot 4= (6m)(4)-(7)(4)\\\\= (6)(4)(m)-28 \ \ \ [\text{By associative property}]\\\\=24m-28](https://tex.z-dn.net/?f=%286m%20-%207%29%5Ccdot%204%3D%20%286m%29%284%29-%287%29%284%29%5C%5C%5C%5C%3D%20%286%29%284%29%28m%29-28%20%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20associative%20property%7D%5D%5C%5C%5C%5C%3D24m-28)
Hence, the required equivalent expression is 24m-28.
Answer:
The small balloon bouquet uses 7 balloons and the large one uses
18 balloons.
Step-by-step explanation:
Let's say that small balloon bouquets are S and large balloon bouquets are L. For the graduation party the employee assembled 6 small bouquets and 6 large bouquets, the total number of balloon used is 150. To put the sentence into an equation will be:
6S + 6L= 150
S+L= 25 ----> 1st equation
For Father's Day, the employee uses 6 small bouquet and 1 large bouquet, the total number of balloons used is 60. The equation will be:
6S + 1L= 60
1L= 60- 6S ----> 2nd equation
We can solve the number of small balloon bouquet by substitute the 2nd equation into 1st. The calculation will be:
S+L = 25
S+ (60-6S)= 25
-5S= 25-60
-5S= -35
S= -35/-5
S=7
Then we can find L by substitute S value to 1st or 2nd equation.
S+L=25
7+L=25
L=18
Hope this helps ;)
Answer:
y=1/2x²
Step-by-step explanation:
y=2x-²
y=1/2x²