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vazorg [7]
3 years ago
5

FG is the midsegment of isosceles ABC, and is the midsegment of trapezoid CDEF. Segments EF, KM and DC are parallel. Find the m

easures of segments BC, GF, CD and KM. Show your work and describe any properties or theorems you use.

Mathematics
1 answer:
Readme [11.4K]3 years ago
4 0
BC=60 cm because FG is the midsegment of triangle ABC so it separates the sides of the triangle into two equal segments and 30(2)=60.
GF=22 cm because according to the Triangle Midsegment Theorem, GF=1/2(AC). GF=1/2(44 cm). GF=22 cm. Next, we can conclude EG and DA are 22 cm because the diagram marks them as congruent. So CD=44 cm+22 cm=66 cm. Then, we find that EF=EG+GF=22 cm+22 cm=44 cm. So, using the Trapezoid Midsegment Theorem, we know that KM=1/2(DC+EF). KM=1/2(66 cm+44 cm). KM=1/2(110 cm). KM=55 cm.

Hope this helps and makes sense!
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4 0
3 years ago
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2 years ago
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