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Murljashka [212]
3 years ago
12

Nyatakan tiga bentuk bagi atom karbon dan perbezaan ringkas diantara ketiga-tiga atom karbon tersebut

Chemistry
1 answer:
Montano1993 [528]3 years ago
3 0

Answer:

Berlian, grafit dan fullerenes.

Penjelasan:

Tiga bentuk atom karbon adalah berlian, grafit dan fullerenes. Ketiga-tiga atom karbon ini adalah bentuk atom karbon allotrophic. Perbezaan utama antara atom karbon adalah berikut:

Ketiga-tiga bentuk allotrophic mempunyai sifat kimia yang sama tetapi sifat fizikalnya berbeza antara satu sama lain. Berlian adalah yang paling sukar sementara grafit lembut. Dalam berlian, satu atom karbon berkongsi elektron dengan empat atom karbon yang lain sementara dalam grafit, satu atom karbon berkongsi elektron dengan tiga atom karbon dan fulleren adalah atom di mana satu atom karbon dihubungkan dengan beberapa atom karbon melalui ikatan kovalen. Ketiga-tiga atom karbon padat pada suhu bilik.

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The right answer is Sillicon.

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It is a semi-metal, ie it does not meet all the criteria to be defined as being a metal.

It has four free electrons in the last orbit, so it is able to form four covalent bonds. (the carbon can form 4 covalent bonds but it is not a semi-metal)

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You have 125 g of a certain seasoning and are told that it contains 70.0 g of salt. What is the peroentage of salt by mass in th
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21 mL It required 42.35 mL of H2SO4 to neutralize 21.17 mL of 0.5000 M NaOH. Calculate the concentration of H2SO4
bija089 [108]
The balanced equation for the above reaction is 
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number of NaOH moles required-0.5000 M / 1000 mL/L x 21.17 mL = 0.010585 mol
According to stoichiometry, acid moles required are 1/2 of the base moles reacted
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Therefore in 1 L solution - (0.010585) /2 / 42.35 mL x 1000 mL/L = 0.125 M
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5 0
3 years ago
Which component of a plant makes the cell walls around plant cells tough and allows branches, stems, and leaves to be strong
Vsevolod [243]
<h3><u>Answer;</u></h3>

Cellulose

<h3><u>Explanation</u>;</h3>
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8 0
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A titration of 25.0 mL of a solution of the weak base aniline, C6H5NH2, requires 25.67 mL of 0.175 M HCl to reach the equivalenc
Lorico [155]

Answer:

a. 0.180M of C₆H₅NH₂

b. 0.0887M C₆H₅NH₃⁺

c. pH = 2.83

Explanation:

a. Based in the chemical equation:

C₆H₅NH₂(aq) + HCl(aq) → C₆H₅NH₃⁺(aq) + Cl⁻(aq)

<em>1 mole of aniline reacts per mole of HCl</em>

Moles required to reach equivalence point are:

Moles HCl = 0.02567L ₓ (0.175mol / L) = 4.492x10⁻³ moles HCl = moles C₆H₅NH₂

As the original solution had a volume of 25.0mL = 0.0250L:

4.492x10⁻³ moles C₆H₅NH₂ / 0.0250L = 0.180M of C₆H₅NH₂

b. At equivalence point, moles of C₆H₅NH₃⁺ are equal to initial moles of C₆H₅NH₂, that is 4.492x10⁻³ moles

But now, volume is 25.0mL + 25.67mL = 50.67mL = 0.05067L. Thus, molar concentration of C₆H₅NH₃⁺ is:

[C₆H₅NH₃⁺] = 4.492x10⁻³ moles / 0.05067L = 0.0887M C₆H₅NH₃⁺

c. At equivalence point you have just 0.0887M C₆H₅NH₃⁺ in solution. C₆H₅NH₃⁺ has as equilibrium in water:

C₆H₅NH₃⁺(aq) + H₂O(l) → C₆H₅NH₂ + H₃O⁺

Where Ka = Kw / Kb = 1x10⁻¹⁴ / 4.0x10⁻¹⁰ =

<em>2.5x10⁻⁵ = [C₆H₅NH₂] [H₃O⁺] / [C₆H₅NH₃⁺]</em>

When the system reaches equilibrium, molar concentrations are:

[C₆H₅NH₃⁺] = 0.0887M - X

[C₆H₅NH₂] = X

[H₃O⁺] = X

Replacing in Ka formula:

2.5x10⁻⁵ = [X] [X] / [0.0887M - X]

2.2175x10⁻⁶ - 2.5x10⁻⁵X = X²

0 = X² + 2.5x10⁻⁵X - 2.2175x10⁻⁶

Solving for X:

X = -0.0015 → False solution. There is no negative concentrations.

X = 0.001477 → Right solution.

As [H₃O⁺] = X, [H₃O⁺] = 0.001477

Knowing pH = -log [H₃O⁺]

pH = -log 0.001477

<h3>pH = 2.83</h3>

7 0
2 years ago
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