Answer:
Electronegativity decrease in group from top to bottom
Explanation:
Answer:
219.95 °C
Explanation:
Given data:
Volume of gas = 9.71 L
Initial pressure = 209 torr (209/760 = 0.275 atm)
Initial temperature = 10.1 °C (10.1 +273 = 283.1 K)
Final temperature = ?
Final pressure = 364 torr (364/760 =0.479 atm)
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
0.275 atm / 283.1 K = 0.479 atm/T₂
T₂ = 0.479 atm × 283.1 K/ 0.275 atm
T₂ = 135.6 atm. K /0.275 atm
T₂ = 493.1 K
Kelvin to °C:
493.1 K - 273.15 = 219.95 °C
Fossils are fundamental to the geologic time scale. The names of most of the eons and eras end in zoic, because these time intervals are often recognized on the basis of animal life. Rocks formed during the Proterozoic Eon may have fossils of relative simple organisms, such as bacteria, algae, and wormlike animals
Spore formation is a form of asexual reproduction used by mushrooms and molds.
During budding, the offspring grows from the body of the parent.
Fragmentation is a form of asexual reproduction that must be followed by regeneration.
Explanation:
Asexual reproduction is the type of reproduction where the gamete formation and fusion have no relevance or existence. It functions on the process of somatic cell division via mitosis and the offsprings are identical to their parents.
The spore formation occurs in fungi through sporangia, bursting open to shed spores, forming into a new young ones. Budding occurs out as an outgrowth of the parent and attains maturity and separates. Fragmentation is the process where the parents fall apart into pieces and regeneration follows.
The effusion rate is 1.125 cm/sec for ammonia.
How to find effusion rate ?
Effusion rate (r1) HCl = 43.2 cm/min
Molar mass (m2) NH3 =17.04g/mole
Molar mass (m1) HCl =36.46g/mole
- Substitute the molar masses of the gases into Graham's law and solve for the ratio.
firstly convert 43.2 cm/min into cm/sec i.e., 0.72 cm/sec
Then,
0.72/r2 =√17.04/36.46
r2= 1.125 cm/sec
Hence, the rate of diffusion of ammonia is 1.125 times faster than the rate of diffusion of hydrogen chloride.
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