The 5.9 L container at STP contains 16.83 g of SO2.
To begin, we must determine how many moles of SO2 are contained in the 5.9 L container.
At standard temperature and pressure (STP), one mole of SO2 equates to 22.4 liters.
5.9 L = 5.9 / 22.45.9 L = 0.26 moles of SO2 as a result.
The result is that 0.263 moles of SO2 are present in the container.
Following that, we shall determine the mass of 0.263 moles of SO2.
The following are ways to do this:
The mass of SO2 is 32 + (16 2) = 32 + 32= 64 g/mol,
where SO2 Mole = 0.263 Molar.
Molar + Molar Mass Equals Mass
SO2 mass is 16.83 g, or 0.263 of a kilogram.
Therefore, 16.83 g of SO2 are present in the 5.9 L container at STP.
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Answer:
Mg²⁵ = 10.00%
Mg²⁶ = 45.04%
Mg²⁴ = 44.96%
Explanation:
Given data:
Atomic mass of Mg²⁶ = 25.983
Atomic mass of Mg²⁵ = 24.986
Atomic mass of Mg²⁴ = 23.985
Abundance of Mg²⁵ = 10.00%
Abundance of Mg²⁶ = ?
Abundance of Mg²⁴ = ?
Solution:
Average atomic weight of Mg = 25.983 + 24.986+ 23.985 / 3
Average atomic weight of Mg = 74.954/3
Average atomic weight of Mg = 24.985 amu
Abundance of
Mg²⁵ = 10.00
Mg²⁶ = x
Mg²⁴ = 100- 10 - x = 90 -x
Formula:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100
24.985 = (0.1×24.986)+(90-x×23.985) + ( x ×25.983 ) /100
24.985 = 249.86 + 2158.65 - 23.985x + 25.983x / 100
24.985 = 2408.51 + 1.998 x / 100
2498.5 = 2408.51 + 1.998 x
1.998 x = 2498.5 - 2408.51
1.998 x = 89.99
x = 89.99 /1.998
x = 45.04
Now we put the value of x:
Mg²⁵ = 10.00
Mg²⁶ = x (45.04)
Mg²⁴ = 90 -x (90 - 45.04 = 44.96)
Answer:
<h2>134km = 13400000cm</h2><h2>35g = 35000000ug</h2><h2>0.65mmol = 0.00065mol</h2>