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Alexxandr [17]
4 years ago
5

Which is an example of an exothermic process? boiling of milk melting of wax freezing of water evaporation of water heating of w

ater
Chemistry
2 answers:
Irina18 [472]4 years ago
8 0

A.) Boiling of milk produces heat on the outside which is exothermic

ratelena [41]4 years ago
7 0

Answer: Option (a) is the correct answer.

Explanation:

A process in which heat is absorbed by the atoms of a substance is known as endothermic process. Here, energy of products is more than the energy of reactants.

Whereas a process in which heat is released by the atoms of a substance is known as exothermic process. Here, energy of reactants is more than the energy of products.

So, when milk boils then energy is releasing in the form of steam. When wax melts then it means heat is absorbed by wax molecules.

When water freezes then also energy is absorbed due to which molecules are coming closer to each other.

Whereas evaporation and heating of water will are also endothermic as heat is absorbed in both the cases.

Thus, we can conclude that boiling of milk  is an example of an exothermic process.

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if the pressure of a gas at constant volume is 3.5 atm at 100°c, what will the pressure be if the tempature is changed to 250°c?
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4 0
3 years ago
Read 2 more answers
A sample of gas occupies a volume of 61.5 mL . As it expands, it does 130.1 J of work on its surroundings at a constant pressure
Lesechka [4]

Answer:

the final volume of the gas is V_2 = 1311.5 mL

Explanation:

Given that:

a sample gas has an initial volume of 61.5 mL

The workdone = 130.1 J

Pressure = 783 torr

The objective is to determine the final volume of the gas.

Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.

Converting the external pressure to atm ; we have

External Pressure P_{ext}:

P_{ext} = 783 \ torr \times \dfrac{1 \ atm}{760 \ torr}

P_{ext} = 1.03 \ atm

The workdone W = P_{ext}V

The change in volume ΔV= \dfrac{W}{P_{ext}}

ΔV = \dfrac{130.1 \ J  \times \dfrac{1 \ L  \ atm}{ 101.325 \ J}  }{1.03 \ atm }

ΔV = \dfrac{1.28398717 }{1.03  }

ΔV = 1.25 L

ΔV = 1250 mL

Recall that the initial  volume = 61.5 mL

The change in volume V is \Delta V = V_2 -V_1

-  V_2= -  \Delta V  -V_1

multiply through by (-), we have:

V_2=   \Delta V+V_1

V_2 =  1250 mL + 61.5 mL

V_2 = 1311.5 mL

∴ the final volume of the gas is V_2 = 1311.5 mL

5 0
3 years ago
B. Calculate how many atoms of hydrogen are in 1. 75 moles of glucose (c6h12o6).
ycow [4]

Answer:

1.26x10^25 atoms of hydrogen

Explanation:

because there are 12 atoms of hydrogen in a molecule of glucose, multiply 12 by Avogadro's number (6.02x10^23) to get how many molecules of hydrogen there are in a mole of glucose. Then multiply that number by 1.75, which is the number of moles of glucose there is in this problem.

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3 years ago
Please help explain and don't answer if you don't know. thank you
ipn [44]

Answer:

The group 18 elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). These elements are non-reactive and are called noble gases as they have their outermost orbit complete. Due to stable electronic configuration they hardly react with other elements.The name comes from the fact that these elements are virtually unreactive towards other elements or compounds.The group 18 elements are called noble or inert gases. As the name suggests these are inert because chemically they are very less reactive or not at all reactive.The full valence electron shells of these atoms make the noble gases extremely stable.

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