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Delicious77 [7]
3 years ago
11

What kind of bond is present in HCI

Chemistry
1 answer:
BigorU [14]3 years ago
7 0
The correct answer is D. Covalent Bond
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________ is a measure of the amount of matter in an object.
Zepler [3.9K]
Mass i think hope and this helps u
6 0
3 years ago
Read 2 more answers
How do you calculate mass using density and volume?
vazorg [7]

D = M/v
M = Dv
V = M/D
7 0
3 years ago
CO, + H2O –H^2 CO^3 The reaction is which type of chemical reaction?​
gulaghasi [49]

Answer:

Combination reaction or synthesis reaction

Explanation:

Given reaction:

                 CO  +  H₂O  →  H₂CO₃

The type of reaction shown above is a combination or synthesis reaction. A combination reaction is one in which a single product is formed from two or more reactants.

In the given reaction carbon monoxide combines with water to produce hydrogen carbonate.

The formation of compounds from the union of their constituent elements falls into this category of reactions.

4 0
2 years ago
How can you use a heating curve to find the melting and boiling point
lana66690 [7]

Answer:

Explanation:

A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. ... The first change of phase is melting, during which the temperature stays the same while water melts. The second change of phase is boiling, as the temperature stays the same during the transition to gas.

3 0
3 years ago
131i has a half-life of 8.04 days. assuming you start with a 1.53 mg sample of 131i, how many mg will remain after 13.0 days ___
inn [45]
For this problem we can use half-life formula and radioactive decay formula.

Half-life formula,
t1/2 = ln 2 / λ

where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days

Hence,         
8.04 days    = ln 2 / λ                         
λ   = ln 2 / 8.04 days

Radioactive decay law,
Nt = No e∧(-λt)

where, Nt is amount of compound at t time, No is amount of compound at  t = 0 time, t is time taken to decay and λ is radioactive decay constant.

Nt = ?
No = 1.53 mg
λ   = ln 2 / 8.04 days = 0.693 / 8.04 days
t    = 13.0 days 

By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
Nt = 0.4989 mg = 0.0.499 mg

Hence, mass of remaining sample after 13.0 days = 0.499 mg

The answer is "e"

8 0
2 years ago
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