Answer:
Amylase.
Explanation:
The process of digestion begin to start in mouth when food mix with saliva. An enzyme is released which is called Amylase help in digestion of carbohydrates.
Where is the table? I dont know what to classify
Answer:
c =0.2 J/g.°C
Explanation:
Given data:
Specific heat of material = ?
Mass of sample = 12 g
Heat absorbed = 48 J
Initial temperature = 20°C
Final temperature = 40°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 40°C -20°C
ΔT = 20°C
48 J = 12 g×c×20°C
48 J =240 g.°C×c
c = 48 J/240 g.°C
c =0.2 J/g.°C
Answer:
A. The pressure will increase 4 times. P₂ = 4 P₁
B. The pressure will decrease to half its value. P₂ = 0.5 P₁
C. The pressure will decrease to half its value. P₂ = 0.5 P₁
Explanation:
Initially, we have n₁ moles of a gas that occupy a volume V₁ at temperature T₁ and pressure P₁.
<em>What would happen to the gas pressure inside the cylinder if you do the following?</em>
<em />
<em>Part A: Decrease the volume to one-fourth the original volume while holding the temperature constant. Express your answer in terms of the variable P initial.</em>
V₂ = 0.25 V₁. According to Boyle's law,
P₁ . V₁ = P₂ . V₂
P₁ . V₁ = P₂ . 0.25 V₁
P₁ = P₂ . 0.25
P₂ = 4 P₁
<em>Part B: Reduce the Kelvin temperature to half its original value while holding the volume constant. Express your answer in terms of the variable P initial.</em>
T₂ = 0.5 T₁. According to Gay-Lussac's law,
![\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}\\\frac{P_{1}}{T_{1}} =\frac{P_{2}}{0.5T_{1}}\\\\P_{2}=0.5P_{1}](https://tex.z-dn.net/?f=%5Cfrac%7BP_%7B1%7D%7D%7BT_%7B1%7D%7D%20%3D%5Cfrac%7BP_%7B2%7D%7D%7BT_%7B2%7D%7D%5C%5C%5Cfrac%7BP_%7B1%7D%7D%7BT_%7B1%7D%7D%20%3D%5Cfrac%7BP_%7B2%7D%7D%7B0.5T_%7B1%7D%7D%5C%5C%5C%5CP_%7B2%7D%3D0.5P_%7B1%7D)
<em>Part C: Reduce the amount of gas to half while keeping the volume and temperature constant. Express your answer in terms of the variable P initial.</em>
n₂ = 0.5 n₁.
P₁ in terms of the ideal gas equation is:
![P_{1}=\frac{n_{1}.R.T_{1}}{V_{1}}](https://tex.z-dn.net/?f=P_%7B1%7D%3D%5Cfrac%7Bn_%7B1%7D.R.T_%7B1%7D%7D%7BV_%7B1%7D%7D)
P₂ in terms of the ideal gas equation is:
![P_{2}=\frac{n_{2}.R.T_{1}}{V_{1}}=\frac{0.5n_{1}.R.T_{1}}{V_{1}}=0.5P_{1}](https://tex.z-dn.net/?f=P_%7B2%7D%3D%5Cfrac%7Bn_%7B2%7D.R.T_%7B1%7D%7D%7BV_%7B1%7D%7D%3D%5Cfrac%7B0.5n_%7B1%7D.R.T_%7B1%7D%7D%7BV_%7B1%7D%7D%3D0.5P_%7B1%7D)