Answer:
Explanation:
1
When elements in group 2 react with Iodine, a salt MI_2 is formed
2
When they react with water, Hydrogen gas is released
3
When they react with Oxygen, an Oxide, MO is formed
4
The most vigorously reactive metal in group 2 is Barium, Ba. Reactivity increases as one moves downward in group 2
5
The most metallic element is Barium, Ba. This is because in the periodic table, metallic strength of metals increases as one moves down the table.
Answer:
its compound option c compound comprises of two or more atoms
Answer: True
Explanation:
The speed of light in a material medium depends on its molecular structure, in particular its electromagnetic properties, electrical and magnetic permeability. These properties may have different values for different wavelengths or frequencies of the incident light.
In this way,<u> the speed of light depends on the medium and reaches its maximum value in a vacuum</u>, so that, it will be lower in a material medium . In the vacuum (or in the air) the speed of light is 3 x 10⁸ m / s and in any other medium its value is lower.
<u>To characterize the particularities of the propagation of light in the media</u>, the refractive index is introduced
,
n = c / v
where c is <u>speed of light in a vacuum</u> and v is t<u>he speed of light in the medium</u> considered
. So the speed of light in a medium is given by the refractive index whose value is always greater than 1.
Answer:
In chemistry, catenation is the bonding of atoms of the same element into a series, called a chain. A chain or a ring shape may be open if its ends are not bonded to each other, or closed if they are bonded in a ring
Explanation:
Answer:
- <u>Yes, it is 14. g of compound X in 100 ml of solution.</u>
Explanation:
The relevant fact here is:
- the whole amount of solute disolved at 21°C is the same amount of precipitate after washing and drying the remaining liquid solution: the amount of solute before cooling the solution to 21°C is not needed, since it is soluble at 37°C but not soluble at 21°C.
That means that the precipitate that was thrown away, before evaporating the remaining liquid solution under vacuum, does not count; you must only use the amount of solute that was dissolved after cooling the solution to 21°C.
Then, the amount of solute dissolved in the 600 ml solution at 21°C is the weighed precipitate: 0.084 kg = 84 g.
With that, the solubility can be calculated from the followiing proportion:
- 84. g solute / 600 ml solution = y / 100 ml solution
⇒ y = 84. g solute × 100 ml solution / 600 ml solution = 14. g.
The correct number of significant figures is 2, since the mass 0.084 kg contains two significant figures.
<u>The answer is 14. g of solute per 100 ml of solution.</u>
