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Degger [83]
2 years ago
12

Answer number 1 please

Chemistry
1 answer:
kkurt [141]2 years ago
6 0

Answer:

C. is the answer simple.

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If you start with 0.30 m mn2 , at what ph will the free mn2 concentration be equal to 4.6 x 10-11 m?
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If you start with 0.30 m Mn₂ , at 12.5 pH, free Mn₂ concentration be equal to 4.6 x 10⁻¹¹ m

Initial molarity of Mn₂ = 0.30 M

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Ksp [Mn(OH)₂] = 4.6 x 10⁻¹⁴ (standard value)

Write the ionic equation

    Mn(OH)₂   →    Mn⁺² + 2OH⁻

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We will calculate the concentration of OH⁻ by using Ksp expression

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Now calculate pH

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   pH = 14 - 1.5

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You can also learn about molarity from the following question:

brainly.com/question/14782315

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