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bixtya [17]
3 years ago
14

What is the factored form of the expression? 4x^2-81y^2

Mathematics
2 answers:
Tasya [4]3 years ago
4 0
4x^2-81y^2 

(2x)^2-(9y)^2
 

(2x+9y)(2x-9y)
erik [133]3 years ago
4 0

4x {}^{2}  - 81y {}^{2}
Write the expressions 4 & 81 in exponential form with an exponent of 2.

= 2 {}^{2} x {}^{2}  - 9 {}^{2} y {}^{2}
Multiply the terms with equal exponents by multiplying their bases.

= (2x) {}^{2}  - (9y) {}^{2}
Using
a {}^{2}  - b {}^{2}  = (a - b)(a + b)
Factor the expression.

= (2x - 9y) \times (2x + 9y)

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Simplify thefollowing algebraic expression 6(2y +8) -2 (3y
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6(y+8) is the answer but you didn’t finish the equation so
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3 years ago
I need help with this question please and thank you
marissa [1.9K]

Answer:

y = -1x + 3 or f(x) = -1x + 3

Step-by-step explanation:

Rise/run = 3/-3 =<em> <u>-1</u></em>

Crosses the y-axis at <em><u>3</u></em>

y = <em><u>-1</u></em>x + <em><u>3</u></em> or f(x) = <em><u>-1</u></em>x + <em><u>3</u></em>

8 0
3 years ago
Read 2 more answers
Tom Harding is a proofreader. He is paid $0.23 for every page he proofs. What is Tom's total pay for a week in which he proofrea
natka813 [3]
Alrighty, what I was always taught was to start by writing out what you know from the question.

What I know:
-Tom is paid $0.23 for every page of proofs.
-He proofreads 1,992 pages.

In order to figure out how much money Tom has made, we need to multiply 0.23 by 1,992. Multiplying allows us to see the total amount of money made by proofreading x amount of pages - for every page he proofreads, he makes $0.23.
0.23×1992=458.16

Therefore, Tom made $458.16.

Hope this helps!

3 0
3 years ago
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

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2 years ago
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Rzqust [24]
The answer is going to be 3,495
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