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Setler79 [48]
4 years ago
11

Which elements are not balanced in this equation MgO + 2 LiCl = MgCl2 + Li2O

Chemistry
2 answers:
nikitadnepr [17]4 years ago
8 0
B All elements are balanced
ruslelena [56]4 years ago
6 0
This question is about stoichiometry, the ratio of compounds in a reaction. The most important thing that comes out of physics relating to this is the principle of Conservation of Energy, that is energy cannot be created or destroyed, only transferred from one form to another.

This can mean a lot of different things depending on the context, usually to explain why perpetual motion is inpossible - energy transfers are never 100% efficient and as energy cannot be expressly created, the useful energy in an isolated system must dwindle (if you are interested that is called entropy).

But in a chemistry context, for stable atoms such as these where matter remains matter and energy remains energy, it leads to the principle of Conservation of Mass. That is to say there are as many atoms of each type to start with as there are to finish with.

This is why balancing is so important. You wouldn't react two oxygen atoms together (hypothetically) to form two O2 molecules because that would start with 2 atoms and end with 4. Similarly you wouldn't (excluding nuclear fusion reactions) react two magnesium atoms together to produce a Cl2 molecule because the mass has changed (an Mg has a different mass to a Cl).

Taking note of the number of each type of atom on each side of the equation, we find there is the same number always. This shows the equation is balanced. Conservation of Mass, and by extension Conservation of Energy, is satisfied so the answer is B.
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Look at the four chemical reactions.
Schach [20]

Answer:

The answer is Reaction 2

Explanation:

5 0
3 years ago
If a car is going at a speed of 36 km/hr. what is the speed in m/s
blsea [12.9K]

To convert km/h into m/s = 5/18


36×5/18


10 m/s

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4 years ago
The trait that shows up in the first generation.<br> Recessive<br> Dominant<br> Ok
topjm [15]

Answer:

Dominant

Explanation:

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3 0
3 years ago
Consider this reaction:
aleksklad [387]

Answer:   0.0345 sec

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[H_3PO_4]^2

k= rate constant = 46.6s^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

for completion of 20 % of reaction

t=\frac{2.303}{46.6}\log\frac{0.660}{\frac{20}{100}\times 0.660}

t=\frac{2.303}{46.6}\log\frac{0.660}{0.132}

t=0.0345sec

The time taken for the concentration of H_3PO_4 to decrease to 20% to its natural value is 0.0345 sec

6 0
3 years ago
Natural gas burns in air to form carbon dioxide and water, releasing heat. CH4(g)+2O2(g)→CO2(g)+2H2O(g) ΔHrxn = -802.3 kJ.
Olenka [21]

Answer:

1) Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.

2) Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.

Explanation:

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g) ,\Delta H_{rxn} =-802.3 kJ

1) Minimum mass of  methane required to raise the temperature of water by 21.0°C.

Mass of water = m = 45.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 21.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

Q=mc\Delta T= 45.0 g\times 4.18 J/g^oC\times 21.0^oC

Q = 3,950.1 J = 3.9501 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 3.950.1 kJ of heat will be given by:

=\frac{3.950.1 kJ}{802.3 kJ}=0.004923 mol

Mass of 0.004923 moles of methane :

0.004923 mol × 16 g/mol=0.0788 g

Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.

2) Minimum mass of  methane required to raise the temperature of water by 26.0°C.

Mass of water = m = 50.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 26.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

Q=mc\Delta T= 50.0 g\times 4.18 J/g^oC\times 26.0^oC

Q = 5,434 J= 5.434 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 5.434 kJ of heat will be given by:

=\frac{5.434 kJ}{802.3 kJ}=0.006773 mol

Mass of 0.006773 moles of methane :

0.006773 mol × 16 g/mol= 0.108 g

Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.

6 0
4 years ago
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