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Setler79 [48]
3 years ago
11

Which elements are not balanced in this equation MgO + 2 LiCl = MgCl2 + Li2O

Chemistry
2 answers:
nikitadnepr [17]3 years ago
8 0
B All elements are balanced
ruslelena [56]3 years ago
6 0
This question is about stoichiometry, the ratio of compounds in a reaction. The most important thing that comes out of physics relating to this is the principle of Conservation of Energy, that is energy cannot be created or destroyed, only transferred from one form to another.

This can mean a lot of different things depending on the context, usually to explain why perpetual motion is inpossible - energy transfers are never 100% efficient and as energy cannot be expressly created, the useful energy in an isolated system must dwindle (if you are interested that is called entropy).

But in a chemistry context, for stable atoms such as these where matter remains matter and energy remains energy, it leads to the principle of Conservation of Mass. That is to say there are as many atoms of each type to start with as there are to finish with.

This is why balancing is so important. You wouldn't react two oxygen atoms together (hypothetically) to form two O2 molecules because that would start with 2 atoms and end with 4. Similarly you wouldn't (excluding nuclear fusion reactions) react two magnesium atoms together to produce a Cl2 molecule because the mass has changed (an Mg has a different mass to a Cl).

Taking note of the number of each type of atom on each side of the equation, we find there is the same number always. This shows the equation is balanced. Conservation of Mass, and by extension Conservation of Energy, is satisfied so the answer is B.
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3 years ago
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A titration of 25.0 mL of a solution of the weak base aniline, C6H5NH2, requires 25.67 mL of 0.175 M HCl to reach the equivalenc
Lorico [155]

Answer:

a. 0.180M of C₆H₅NH₂

b. 0.0887M C₆H₅NH₃⁺

c. pH = 2.83

Explanation:

a. Based in the chemical equation:

C₆H₅NH₂(aq) + HCl(aq) → C₆H₅NH₃⁺(aq) + Cl⁻(aq)

<em>1 mole of aniline reacts per mole of HCl</em>

Moles required to reach equivalence point are:

Moles HCl = 0.02567L ₓ (0.175mol / L) = 4.492x10⁻³ moles HCl = moles C₆H₅NH₂

As the original solution had a volume of 25.0mL = 0.0250L:

4.492x10⁻³ moles C₆H₅NH₂ / 0.0250L = 0.180M of C₆H₅NH₂

b. At equivalence point, moles of C₆H₅NH₃⁺ are equal to initial moles of C₆H₅NH₂, that is 4.492x10⁻³ moles

But now, volume is 25.0mL + 25.67mL = 50.67mL = 0.05067L. Thus, molar concentration of C₆H₅NH₃⁺ is:

[C₆H₅NH₃⁺] = 4.492x10⁻³ moles / 0.05067L = 0.0887M C₆H₅NH₃⁺

c. At equivalence point you have just 0.0887M C₆H₅NH₃⁺ in solution. C₆H₅NH₃⁺ has as equilibrium in water:

C₆H₅NH₃⁺(aq) + H₂O(l) → C₆H₅NH₂ + H₃O⁺

Where Ka = Kw / Kb = 1x10⁻¹⁴ / 4.0x10⁻¹⁰ =

<em>2.5x10⁻⁵ = [C₆H₅NH₂] [H₃O⁺] / [C₆H₅NH₃⁺]</em>

When the system reaches equilibrium, molar concentrations are:

[C₆H₅NH₃⁺] = 0.0887M - X

[C₆H₅NH₂] = X

[H₃O⁺] = X

Replacing in Ka formula:

2.5x10⁻⁵ = [X] [X] / [0.0887M - X]

2.2175x10⁻⁶ - 2.5x10⁻⁵X = X²

0 = X² + 2.5x10⁻⁵X - 2.2175x10⁻⁶

Solving for X:

X = -0.0015 → False solution. There is no negative concentrations.

X = 0.001477 → Right solution.

As [H₃O⁺] = X, [H₃O⁺] = 0.001477

Knowing pH = -log [H₃O⁺]

pH = -log 0.001477

<h3>pH = 2.83</h3>

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3 years ago
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Answer : first opinion and also last
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AnnZ [28]

Answer: Avogrado's Constant

Explanation:

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