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Leviafan [203]
3 years ago
12

Does seasonal temperature affect tides?

Chemistry
2 answers:
Helga [31]3 years ago
8 0

I just took the quiz it's experimental

hodyreva [135]3 years ago
7 0
The last on experimental
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Why do we use scientific notation or scientific exponential numbers in math calculations?
seraphim [82]
I believe the answer is: in order not to write very big or very small number values
6 0
3 years ago
Convert 512 kilograms to milligrams.<br><br> 0.000512<br> 0.512<br> 512,000<br> 512,000,000
olga55 [171]
The answer is D! 512000000
5 0
3 years ago
Read 2 more answers
Picture this in your mind as you read it: You weigh an empty, clean, dry beaker on the balance (scale). It weighs 32.15 grams. Y
AleksAgata [21]

Answer:

2.25 g

Explanation:

The mass of the solid X must be the total mass (beaker + solid X) less than the mass of the beaker. Then:

mass of the solid X = 34.40 - 32.15

mass of the solid X = 2.25 g

The difference of 0.25 g must occur for several problems: an incorrect weight in the balance, the configuration of the balance, the solid can be hydrophilic and absorbs water, and others.

6 0
3 years ago
scandium47 has a half-life of 35s. suppose you have a 45g sample of scadium 47 how much of the sample remains unchanged after 14
Mars2501 [29]

 The much  of the sample that would remain  unchanged  after 140 seconds is 2.813 g

Explanation

Half life  is time taken for the quantity  to reduce  to half its original value.

if the half life  for Scandium  is 35 sec, then the number  of half life in 140 seconds

=140 sec/ 35 s = 4 half life

Therefore 45 g after first half life = 45 x1/2 =22.5 g

               22.5 g after second half life = 22.5 x 1/2 =11.25 g

            11.25 g after third half life = 11.25 x 1/2 = 5.625 g

             5.625 after  fourth half life = 5.625 x 1/2 = 2.813

therefore 2.813 g  of Scandium 47 remains  unchanged.

4 0
2 years ago
134 grams of nitric acid is added to 512 grams of water. Calculate the molality of nitric acid.
Nana76 [90]

Answer:   4.15234 m

512 g H2O * \frac{1 kg}{1000 g} = 0.512 kg H2O

Nitric Acid:  HNO3 = 1.008 + 14.007 + 3(15.999) = 63.012 g/mol

H = 1.008 g/mol

N = 14.007 g/mol

O3 = 3*15.999

134 g HNO₃ * \frac{mol}{63.012 g} = 2.126 mol

m = \frac{2.126  mol}{0.512  kg} = 4.15234 m

6 0
3 years ago
Read 2 more answers
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