The second step is to calculate the mass of a given element ammonium nitrate (NH4NO3). We will calculate the masses of all three
elements. The molar mass of each element is given below: molar mass of N: 14.0 g/mol molar mass of H: 1.0 g/mol molar mass of O: 16.0 g/mol Identify the number of moles of each element present in one mole of NH4NO3. # moles N: 2 # moles H: 4 # moles O: 3 Calculate the mass of each element in the compound by multiplying its molar mass by the number of moles of the element present in one mole of the compound. mass N = g mass H = g mass O = g
Since we already have the counts of the number of moles of each element in 1 mole of ammonium nitrate (which are 2 mol N, 4 mol H, 3 mol O), we multiply each of these by the molar masses: N has a molar mass of 14.0 g/mol, so multiplying by 2 mol N gives 28.0 g N H has a molar mass of 1.0 g/mol, so multiplying by 4 mol H gives 4.0 g H O has a molar mass of 16.0 g/mol, so multiplying by 3 mol O gives 48.0 g O So there are 28.0 g N, 4.0 g H, and 48.0 g O. (The total mass would be 80.0 g ammonium nitrate.)
