Answer:
a) I believe it has a volume of 25 ml. I found the value by subtracting 40 from 65.
Hope this Helps!
<em>-kiniwih426</em>
Answer:
H2 + I2 --> 2HI
Explanation:
The two reactants are diatomic molecules because they contain two atoms of the same element. Therefore, they would need to have a subscript of "2" next to their symbols.
When balancing an equation, you want the same amount and type of atoms on both sides. By adding a coefficient of "2" in front of the product, two H's and two I's are now on both sides.
Answer:
Potassium Nitride is composed of the greatest number of atoms.
Explanation:
In order to find the number of atoms present in each compound we will write down their molecular formulas and then we will add up the number of atoms present in them.
A: Dinitrogen Monoxide:
Chemical formula of Dinitrogen Monoxide is N₂O. Therefore, it contains two atoms of Nitrogen and one atom of oxygen Hence, in total it contains 3 atoms.
B: Sodium Chloride:
Chemical formula of Sodium Chloride is NaCl. Therefore, it contains one atom of Sodium and one atom of Chlorine Hence, in total it contains 2 atoms.
C: Potassium Nitride:
Chemical formula of Dinitrogen Monoxide is K₃N. Therefore, it contains three atoms of Potassium and one atom of Nitrogen Hence, in total it contains 4 atoms.
D: Carbon Dioxide:
Chemical formula of Carbon Dioxide is CO₂. Therefore, it contains one atom of Carbon and two atoms of Oxygen Hence, in total it contains 3 atoms.
<span>Average monthly temperatures and precipitation levels </span>
Answer:
Final temperature = ![43.53^{\circ} C](https://tex.z-dn.net/?f=43.53%5E%7B%5Ccirc%7D%20C)
Explanation:
Given that,
Heat added, Q = 250 J
Mass, m = 30 g
Initial temperature, T₁ = 22°C
The Specific heat of Cu= 0.387 J/g °C
We know that, heat added due to the change in temperature is given by :
![Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T%5C%5C%5C%5CQ%3Dmc%28T_2-T_1%29%5C%5C%5C%5C%5Cdfrac%7BQ%7D%7Bmc%7D%3D%28T_2-T_1%29%5C%5C%5C%5CT_2%3D%5Cdfrac%7BQ%7D%7Bmc%7D%2BT_1)
Put all the values,
![T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C](https://tex.z-dn.net/?f=T_2%3D%5Cdfrac%7B250%7D%7B30%5Ctimes%200.387%7D%2B22%5C%5C%5C%5C%3D43.53%5E%7B%5Ccirc%7D%20C)
So, the final temperature is equal to
.