Answer:
[NaOH} = 0.4 M
Explanation:
In a reaction of neutralization, we determine the equivalence point of the titration. In this case, we have a strong base and a strong acid.
(H₂SO₄, is considered strong, but the first deprotonation is weak)
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
As we have 2 protons in the acid, we need 2 OH⁻ from the base to form 2 molecules of water.
In the equivalence point we know mmoles of base = mmoles of acid
Let's finish the excersise with the formula
25 mL . M NaOH = 28.2 mL . 0.355M
M NaOH = (28.2 mL . 0.355M) / 25 mL → 0.400
<h3>
Answer:</h3>
LiOH(aq) +HCl(aq)→ LiCl(aq) + H₂O(l)
Salt formed is LiCl
<h3>
Explanation:</h3>
- Arrhenius acid refers to a substance that ionizes in water to generate protons or hydrogen ions.
- Examples of Arrhenius acid include acids such as HCl, H₂SO₄ and HNO₃.
- A reaction between Lithium hydroxide and an Arrhenius acid such as HCl will yield a salt and water.
That is;
LiOH(aq) +HCl(aq)→ LiCl(aq) + H₂O(l)
- The salt formed is LiCl
- The reaction is an example of neutralization reaction.
Answer:
b. unsaturated
.
Explanation:
Hello there!
In this case, according to the given information, it turns out necessary for us to bear to mind the definition of each type of solution:
- Supersaturated solution: comprises a large amount of solute at a temperature at which it will be able to crystalize upon standing.
- Unsaturated solution: is a solution in which a solvent is able to dissolve any more solute at a given temperature.
- Saturated solution can be defined as a solution in which a solvent is not capable of dissolving any more solute at a given temperature.
In such a way, since 20 grams of the solute are less than the solubility, we infer this is b. unsaturated, as 33.3 grams of solute can be further added to the 100 grams of water.
Regards!
Answer: m = n·M = 34.7 g
Explanation:
M(Li) = 6.941 g/mol, n = 5 mol
