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wlad13 [49]
3 years ago
5

To answer this question, you will need to write the balanced equation and set up a BCA table. Using appropriate rounding rules,

round your answer to the nearest tenth of a decimal (ex: 10.2 g)
Water decomposes when electrolyzed to produce hydrogen and oxygen gas. If 2.5 grams of water were decomposed, how many grams of oxygen gas should be given off?

A. 4.5g
B. 2.2g
C 1.3g
D 0.1g
Chemistry
1 answer:
Elenna [48]3 years ago
7 0

Water decomposes when electrolyzed to produce hydrogen and oxygen gas. If 2.5 grams of water were decomposed 1.04 grams of oxygen will be formed.

BCA table:

2H_{2}O ⇒ H_{2} + O_{2}

B  0.13        0 + 0

C  -0.13      0.065 + 0.065

A  0             0.065

Explanation:

Balanced equation for water decomposition into hydrogen and oxygen gases

   2H_{2}O ⇒ H_{2} + O_{2}

B  0.13        0 + 0

C  -0.13      0.065 + 0.065

A  0             0.065

Number of moles of water = \frac{mass}{atomic mass of 1 mole}

mass = 2.5 grams

atomic mass= 18 grams

number of moles can be known by putting the values in the formula,

n = \frac{2.5}{18}

  = 0.13 moles

2 moles of water gives one mole of oxygen on decomposition

so, 0.13 moles of water will give x moles of oxygen on decompsition

\frac{1}{2} = \frac{x}{0.13}

x = 0.065 moles of oxygen will be formed.

moles to gram will be calculated as

mass =number of moles x atomic mass

        = 0.065 x 16

         = 1.04 grams of oxygen.

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7 0
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How many grams of glucose are needed to prepare 144.3 mL of a 1.4%(m/v) glucose solution?
Montano1993 [528]

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2.0202 grams

Explanation:

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6 0
3 years ago
Read 2 more answers
A reaction at -6.0 °C evolves 786. mmol of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is co
borishaifa [10]

Answer:

V of Sulfur tetrafluoride is  17.2 L

Explanation:

Given data;

T = -6°C =  267K                                [1° C  = 273 K]

n = 786 mmol of SF4 which is 0.786 mol

P = 1 atm

from ideal gas law  we have

PV = nRT

where n is mole, R is gas constant, V is volume

V = \frac{nRT}{P}V = \frac{0.786 mol \times 0.082 atmL/mol K \times* 267K}{1atm} = 17.2 L

V of Sulfur tetrafluoride is  17.2 L

6 0
3 years ago
A 0.753 g sample of a monoprotic acid is dissolved in water and titrated with 0.250 M NaOH. What is the molar mass of the acid i
Alexeev081 [22]

Answer:

MM_{acid}=140.1g/mol

Explanation:

Hello,

In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

n_{acid}=n_{base} \\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\n_{acid}=V_{base}M_{base}

Thus, solving for the moles of the acid, we obtain:

n_{acid}=0.0215L*0.250\frac{mol}{L}=5.375x10^{-3}mol

Then, by using the mass of the acid, we compute its molar mass:

MM_{acid}=\frac{0.753g}{5.375x10^{-5}mol} \\\\MM_{acid}=140.1g/mol

Regards.

7 0
2 years ago
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