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2 years ago

A $400 tv is on sale for 25% off what is the sale price of the tv

Mathematics

1 answer:

N76 [4]2 years ago

5 0

300.

You can multiply by .75 to get the 25% off.

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How do you compute fractions

Elan Coil [88]

Step 1: Make sure the bottom numbers (the denominators) are the same.
Step 2: Add the top numbers (the numerators), put the answer over the denominator.
Step 3: Simplify the fraction (if needed)

6 0

3 years ago

12/5 as a decimal using long division? A: 1.2 B: 2.4 C:2.6 D: 3/4

Oduvanchick [21]

I believe it's B. If I'm wrong tell me so I can see what I did wrong.

7 0

3 years ago

A model for tumor growth is given by the Gompertz equation dV dt = a (In b-, In V) V where a >0 and b >0 are constants and

Xelga [282]

Answer:

$V(t) = b^{(1-e^{-at})}$

Step-by-step explanation:

We are given the following information in the question:

$\displaystyle\frac{dV}{dt} = a (In b - In V) V$

where a > 0 and b > 0.

$\displaystyle\frac{dV}{dt} = a (In b-In V) V\\\\\displaystyle\frac{dV}{dt} = -aV(ln\frac{V}{b})\\\\\frac{dV}{V(ln\frac{V}{b})} = (-a)dt\\\\\text{Put } ln\frac{V}{b} = z\\\\\text{Integrating both sides}\\\\\int \frac{dV}{V(ln\frac{V}{b})} = \int (-a)dt\\\\\text{We get}\\\\\int \frac{dz}{z} = \int (-a)dt\\\\\\\text{where C is the constant of integration}$

$V(0) = 1~ mm^3\\V(t) = b.e^{e^{-at+C}}\\\text{Putting t =0, V(0) = 1}\\\\V(0) = 1 = b.e^{e^{C}}\\\\V(t) = b^{(1-e^{-at})}$

where v(t) is the required tumor volume as a function of time that has an initial tumor volume of V(0) = 1 cubic mm.

5 0

2 years ago

Complete the conversion. Enter your answer in the box. 8 pt = __ c

Shtirlitz [24]

Answer:

16 cups

Step-by-step explanation:

there are 2 cups in a pint

8x 2= 16

7 0

3 years ago

Read 2 more answers

A culture started with 3000 bacteria. After 4 hours, it grew to 3,600 bacteria. Predict how many bacteria will be present after

Vlad [161]

Hello Shannonrodrigue. You can solve this by setting up an exponential growth equation.

$A = A_ob^t$
$3600 = 3000b^4$

Now we solve for b
$3600 = 3000b^4$
$\frac{3600}{3000} = \frac{3000b^{4}}{3000}$
$\frac{6}{5} = b^4$
$\sqrt[4]{\frac{6}{5}} = \sqrt[4]{b^4}$
$\sqrt[4]{\frac{6}{5}} = b$

Now that we have found b, we can use the equation $A = 3000b^t$ to predict how many bacteria will be present after 10 hours.
$b = \sqrt[4]{\frac{6}{5}}$
t = 10
$A = 3000b^t$
$A = 3000\sqrt[4]{\frac{6}{5}}^{10} = 4732.3228 = 4732$

Answer = 4732

4 0

3 years ago