Answer:
Step-by-step explanation:
a) The objective of the study is test the claim that the average gain in the green fees , lessons or equipment expenditure for participating golf facilities is less than $2,100 under the claim the null and alternative hypothesis are,
H₀ : μ = $2,100
H₀ : μ < $2,100
B) Suppose you selects α = 0.01
The probability that the null hypothesis is rejected when the average gain is $2,100 is 0.01
C) For α = 0.01
specify the rejection region of a large sample test
At the given level of significance 0.01 and the test is left-tailed then rejection level of a large-sample = < - 1.28
Answer:
I believe it's 1.
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
5 - 3[ 2 + (-5)] 2 - 8
Subtract 5 from 2 to get −3.
5 - 3 (-3) × 2 - 8
Multiply 3 and −3 to get −9.
5 - (-9 × 2) - 8
Multiply −9 and 2 to get −18.
5 - (-18) - 8
The opposite of −18 is 18.
5 + 18 - 8
Add 5 and 18 to get 23.
23 - 8
Subtract 8 from 23 to get 15.
15
Hope it helps and have a great day! =D
~sunshine~
Step-by-step explanation:
-5(p + 3/5 ) = -4
-5p - 3/5 *5 = -4
-5p - 3 = - 4
-5p = -4 +3
-5p = -1
therefore p = 1/ 5
