Question

Please helppppppppppppp

Answer 1

The ball's initial velocity must be 28.0 m/s

Explanation:

The motion of the ball in this problem is a projectile motion, so it follows a parabolic path, consisting of two separate motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

First, we study the vertical motion of the ball: since it is a uniformly accelerated motion, we can use the suvat equation  to find the time it takes for the ball to reach the ground,

$s=ut+\frac{1}{2}at^2$  

where  

s = 40 m is the vertical displacement, the height of the cliff (we chose downward as positive direction)  

u = 0 is the initial vertical velocity of the ball

t is the time of flight of the ball

$a=g=9.8 m/s^2$ is the acceleration of gravity  

Solving for t, we find:

$t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(40)}{9.8}}=2.86 s$  

Now we can analyze the horizontal motion: since this is a uniform motion, the horizontal speed is constant, and it is given by

$v_x = \frac{d}{t}$

where:

d = 80 m is the horizontal distance covered by the ball

t = 2.86 s is the time of flight

Substituting,

$v_x = \frac{80}{2.86}=28.0 m/s$

Learn more about projectile motion:

brainly.com/question/8751410

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