Suppose you have 50 grams of isotope with a half life of 2 years. How much is the isotope will you have after 4 years
1 answer:
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Answer:
e. Not enough information to determine
Explanation:
This question is incomplete. Here is the complete question with my solution afterwards;
A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turntable (initially at rest) begins to rotate with its rate of rotation constantly increasing.
What is the first event that will occur?(Assume non-zero frictional force and the same coefficients of friction for both bugs.)
a. The ladybug begins to slide
b. The gentleman bug begins to slide
c. Both bugs begin to slide at the same time
d. Nothing ever happens
e. Not enough information to determine
The centripetal force acting on a rotating body or bugs can be written as,
mass of the corresponding bugs
corresponding radial distance of each bug
angular speed of the turntable
The centripetal force tries to slide the bugs in an outward direction and it is directly proportional to the products of its mass and radial distance from the axis of rotation of the turntable
∝
Since the radial distance from the axis of rotation of the turntable for each bug is given, but the mass is not given, the given information is therefore not enough to determine which bugs will slide first.
Option "e" is correct.
Answer:
= 3,126 m / s
Explanation:
In a crash exercise the moment is conserved, for this a system formed by all the bodies before and after the crash is defined, so that the forces involved have been internalized.
the car has a mass of m = 1.50 kg a speed of v1 = 4.758 m / s and the mass of the train is M = 3.60 kg and its speed v2 = 2.45 m / s
Before the crash
p₀ = m v₁₀ + M v₂₀
After the inelastic shock
= m
+ M
p₀ =
m v₀ + M v₂₀ = m + M
We cleared the end of the train
M = m (v₁₀ - v1f) + M v₂₀
Let's calculate
3.60 v2f = 1.50 (2.15-4.75) + 3.60 2.45
= (-3.9 + 8.82) /3.60
= 1.36 m / s
As we can see, this speed is lower than the speed of the car, so the two bodies are joined
set speed must be
m v₁₀ + M v₂₀ = (m + M)
= (m v₁₀ + M v₂₀) / (m + M)
= (1.50 4.75 + 3.60 2.45) /(1.50 + 3.60)
= 3,126 m / s