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Luba_88 [7]
4 years ago
5

Which molecules are pure elements?

Chemistry
2 answers:
Elenna [48]4 years ago
8 0
Well none since molecules are a group of two or more atoms electrically bonded with one another. However, there are gases that does not naturally bond due to their stability and can be found in nature as pure elements. But these are not considered as molecules.

(By the way, these gases are the noble gases that can be found on the last column of the periodic table) 
Vaselesa [24]4 years ago
4 0

Answer: the molecules formed by one kind of atom are pure elements


Explanation:


1) The definition of molecules is the covalent bonding of two or more atoms.


2) Under that definition you must have at least two atoms to be considered a molecule.


3) Pure elements are the 118 elements that you find in the periodic table: each contain only one kind of atom.


4) Then, molecules of pure elements, are two or more atoms of the same kind linked by covalent bonds.


5) With that these some examples of molecules that are pure elements:


i) O₂

ii) N₂

iii) F₂

iv) Cl₂

v) Br₂

vi) O₃


6) And here some examples of molecules that are not pure elements (there are many, many):


i) CH₄

ii) CH₃CH₂CH₃

ii) CH3CH₂CH₂CH₂CH₂CH₂CH₂CH₃


7) Note that ionic compounds are excluded of the definition of molecules, since they are not formed by covalent bonds but by ionic bonds. For example, NaCl is not a molecule.

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Anybody good at chemistry?
Luba_88 [7]

Answer:

Explanation:

1)

Given data:

Mass of lead = 25 g

Initial temperature = 40°C

Final temperature = 95°C

Cp = 0.0308 j/g.°C

Heat required = ?

Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature = initial temperature

ΔT = 95°C -  40°C

ΔT = 55°C

Q = 25 g × 0.0308 j/g.°C  × 55°C

Q = 42.35 j

2)

Given data:

Mass  = 3.1 g

Initial temperature = 20°C

Final temperature = 100°C

Cp = 0.385 j/g.°C

Heat required = ?

Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature = initial temperature

ΔT = 100°C -  20°C

ΔT = 80°C

Q = 3.1 g × 0.385 j/g.°C  × 80°C

Q = 95.48 j

3)

Given data:

Mass of Al = ?

Initial temperature = 60°C

Final temperature = 30°C

Cp = 0.897 j/g.°C

Heat released = 120 j

Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature = initial temperature

ΔT = 30°C -  60°C

ΔT = -30°C

120 j = m × 0.897 j/g.°C  × -30°C

120 j = m × -26.91  j/g

m = 120 j / -26.91  j/g

m =  4.46 g

negative sign show heat is released.

4)

Given data:

Mass of ice = 1.5 g

Change in temperature  = ?

Cp = 0.502 j/g.°C

Heat added= 30.0 j

Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature = initial temperature

30.0 j = 1.5 g × 0.502 j/g.°C  × ΔT

30.0 j = 0.753 j/°C  × ΔT

30.0 j /0.753 j/°C  = ΔT

39.84 °C  =  ΔT

3 0
3 years ago
What is the mass of a block with a volume of 18 cm^3, and a density of 9.2 g/cm^3?
Semmy [17]

Answer: 165.6grams

Explanation:

Mass of a block = ?

Volume of block = 18 cm^3

Density of block = 9.2 g/cm^3

The density of any object depends on its mass and volume.

i.e Density of block = Mass / volume

9.2 g/cm^3 = Mass / 18 cm^3

Mass = 9.2 g/cm^3 x 18 cm^3

= 165.6 g

Thus, the mass of the block is 165.6grams

6 0
3 years ago
URGENT.
Sergio [31]

Answer:

1. 72.9 atm

2. 0.43937 K

Explanation:

1. Gray- lussacs law is p1/t1=p2/t2 so we use this formula to figure it out by filling in the variables and solving

p1=45.0 atm

t1=323 K

p2= ?

t2=523 K

Now we fill in this in the formula and solve - 45.0 atm/ 323 K = p2/ 523 K

and now we solve for p2 by multiplying 535k by each side to give us p2

2. Using the same formula we get 10.0atm/? = 12.0 atm/ 273.15 k and we divide both sides by 10.0 atm

4 0
3 years ago
A mixture which contains more than one phase is called .
kirza4 [7]
This is a heterogeneous mixture. 

6 0
3 years ago
Read 2 more answers
Consider this equilibrium reaction at 400 K. Br2(g)+Cl2(g)↽−−⇀2BrCl(g)Kc=7.0 If the composition of the reaction mixture at 400 K
Genrish500 [490]

Answer:

Q = 7.0

Q = kc. The reaction is in equilibrium

Explanation:

Based on the reaction:

Br₂ + Cl₂ ⇄ 2BrCl

Equilibrium constant of the reaction, kc, is the ratio of <em>equilibrium concentrations</em> products over reactants powered to its reaction coefficient:

Kc = [BrCl]² / [Br₂] [Cl₂] = 7.0

Now, reaction quotient, Q, is write as the same Kc but the concentrations are actual concentrations:

Q = [BrCl]² / [Br₂] [Cl₂]

Replacing:

Q = [0.00415M]² / [0.00366M] [0.000672M]

Q = 7.0

Now, as Q = Kc = 7.0, the reaction mixture is in equilibrium

4 0
3 years ago
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