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anygoal [31]
2 years ago
15

Why is it difficult to determine earth's inner structure

Chemistry
1 answer:
Lesechka [4]2 years ago
5 0
It is hard because we can't get past the crust, Our machines will burn up at the mantle and so will we. The layers go: crust, mantle, outer core, inner core.
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What would happen if the sand dunes in an area were destroyed?
Komok [63]

Answer:

<u>Our beaches would be unprotected</u>

In the short-term, these artificial sand hills will be destroyed by the elements. Because sand dunes protect inland areas from swells, tides, and winds, they must be protected and defended like national treasures. ... The ocean and the wind can have an unpredictable, destructive force on coastal regions.

- surfertoday

Natural sand dunes play a vital role in protecting our beaches, coastline and coastal developments from coastal hazards such as erosion, coastal flooding and storm damage. Sand dunes protect our shorelines from coastal erosion and provide shelter from the wind and sea spray.

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3 0
2 years ago
Read 2 more answers
List of charge of elements that do not form compound easily​
adelina 88 [10]

Answer:

The highlighted words in the explanation.

Explanation:

A clue comes by considering the noble gas elements, the rightmost column of the periodic table. These elements—helium, neon, argon, krypton, xenon, and radon—do not form compounds very easily, which suggests that they are especially stable as lone atoms. What else do the noble gas elements have in common?

7 0
2 years ago
The question is below
rodikova [14]
The anode is the electrode where the oxidation occurs.

Cathode is the electrode where the reducction occurs.

Equations:

  Mn(2+) + 2e-  --->  Mn(s)                      Eo = - 1.18 V
2Fe(3+) + 2e-  ----> 2 Fe(2+)                2Eo = + 1.54 V

The electrons flow from the electrode with the lower Eo to the electrode with the higher Eo yielding to a positive voltage.

Eo = 1.54 V - (- 1.18) = 1.54 + 1.18 = 2.72

Answer: 2.72 V

3 0
3 years ago
Calculate the energy in joules and calories required to heat 50.0g silver from 106c to 255c. ​
Ganezh [65]

Answer:

Explanation:

use this fromula

q = m c ∆t

m  is mass of silver =50 g

∆t is difference in temperature= 255-106=149

C=  specific heat fo silver ( should be mentioned in your question )

5 0
2 years ago
I need to find the reactants and products for each of these 7 problems. I need it in 3/5 hours help please!!!
Nezavi [6.7K]

Answer:

The arrow points from the reactants to the products, so just follow the arrows.

Explanation:

some have the reactants on the left and the products on the right, and others are the opposite... just know that

reactants---------> products

or

products<-----------reactants

4 0
3 years ago
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