1 times 2900 inches for a car

How many nickel atoms are contained in a 92.02 mole sample

Vitek1552 [10]

Answer:

By definition, and this is what Avogadro's constant tells you, 1 mole of nickel must contain 6.022⋅1023 atoms of nickel.

Explanation:

6 0

2 years ago

One day, after much exercise, my friends and I were thirsty. Upon searching through the refrigerator, we found a variety of liqu

antiseptic1488 [7]

Answer:

Water = compound, Orange juice with extra pulp = suspension, Milk = colloid, Calcium = Element, Iced tea = solution.

Explanation:

3 0

3 years ago

A gas that was heated to 150 Celsius has a new volume of 1587.4 L. What was its volume when its temperature was 100 Celsius?

sdas [7]

Answer:

$\boxed {\boxed {\sf 1058.3 \ L}}$

Explanation:

We are asked to find the new volume of a gas after a change in temperature. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula for this law is:

$\frac {V_1}{T_1}= \frac{V_2}{T_2}$

The gas was heated to 150 degrees Celsius and had a volume of 1587.4 liters.

$\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{T_2}$

The temperature was 100 degrees Celsius, but the volume is unknown.

$\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{100 \textdegree C}$

We are solving for the volume at 100 degrees Celsius, so we must isolate the variable V₂. It is being divided by 100°C and the inverse of division is multiplication. Multiply both sides of the equation by 100°C.

$100 \textdegree C *\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{100 \textdegree C} * 100 \textdegree C$

$100 \textdegree C *\frac {1587.4 \ L }{150 \textdegree C} = V_2$

The units of degrees Celsius cancel.

$100 *\frac {1587.4 \ L }{150 } = V_2$

$100 *10.58266667 \ L = V_2$

$1058.266667 \ L = V_2$

The original measurement of volume has 5 significant figures, so our answer must have the same. For the number we calculated, that is the tenth place. The 6 in the hundredth place to the right tells us to round to 2 up to a 3.

$1058.3 \ L = V_2$

The volume of the gas at 100 degrees Celsius is approximately <u>1058.3 liters.</u>

6 0

3 years ago

Explain why HCl can be a strong electrolyte, but a dilute HCl solution can be a poor conductor?

zloy xaker [14]

Answer:

Because as the concentration is diminished, the capacity to transfer electricity is diminished as well.

Explanation:

Hello!

In this case, since electrolytes are substances that are able to conduct the electricity in aqueous media (solutions in which water is the the solvent) because they have the capacity to form ions with both positive and negative charges, due to the fact that HCl is a strong acid, we notice it is fully ionized in solution and therefore it is a strong electrolyte. However, when the concentration is diminished, we can notice that strength is diminished as well because less ions will have the capacity to transfer the electricity and therefore it'd become a poor conductor or weak electrolyte.

Best regards!

3 0

3 years ago

The production capacity for acrylonitrile (C3H3N) in the United States exceeds 2 million pounds per year. Acrylonitrile, the bui

maw [93]

Answer:

a) 1.44 kg

b) 1.47 kg

Explanation:

a) By the reaction given, the stoichiometry, the molar ratio, is:

2 moles of C3H6 : 2 moles of NH3 : 3 moles of O2 : 2 moles of C3H3N : 6 moles of H2O, or 2:2:3:2:6.

By the mixture given, one or two of the reactants may be in excess, so, we must found which of them is the limiting reactant, the reactant that will be totally consumed.

The molar masses of the compounds are:

C3H6 = 42.0 g/mol

NH3 = 17.0 g/mol

O2 = 32.0 g/mol

C3H3N = 53.1 g/mol

H2O = 18.0 g/mol

Thus, the mass ratio between the reactants will be the molar ratio multiplied by the molar mass:

2 moles of C3H6*42.0 g/mol --- 2 moles of NH3*17.0 g/mol -- 3 moles of O2* 32.0 g/mol

84.0 g of C3H6 -- 34.0 g of NH3 -- 96.0 g of O2

Thus, assuming C3H6 as limiting, let's use the rule of three to find out which would be the masses of the other reactants needed:

84.0 g of C3H6 -- 34.0 g of NH3

1.14 kg -- x

84.0x = 38.76 kg

x = 0.46 kg of NH3

Because there's more NH3 than it's required, NH3 is in excess, and C3H6 is limiting. Let's test using O2 as reference:

84.0 g of C3H6 -- 96.0 f of O2

1.14 kg -- x

84.0x = 109.44

x = 1.30 kg of O2

So, O2 is also in excess, and the limiting reactant is C3H6.

Thus, the molar ratio between C3H6 and C3H3N is 2:2, which is simplified by 1:1, and so the mass ratio is 42 g of C3H6 -- 53.1 g of C3H3N, so the mass of acrylonitrile can be found by a rule of three:

42 g of C3H6 -- 53.1 f of C3H3N

1.14 kg -- x

42x = 60.534

x = 1.44 kg

b) The molar ratio between C3H6 and water is 2:6, which can be simplified by 1:3, thus the mass ratio is 1*42g/mol of C3H6 -- 3*18 g/mol of H2O

42 g of C3H6 -- 54 g of H2O

By a rule of three the mass of water is:

42 g of C3H6 -- 54 g of H2O

1.14 kg -- x

42x = 61.56

x = 1.47 kg

6 0

3 years ago