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atroni [7]
3 years ago
7

The work done to expand a gas is 121 J. During the gas expansion, 402 J of heat is absorbed by the gas sample. Calculate the cha

nge in internal energy (ΔE) of the gas in kJ.
[Hint: ΔE = q + w. Make sure to check the sign conventions.]

ΔE = ___________ kJ.
Chemistry
1 answer:
butalik [34]3 years ago
7 0

Answer: 3.50

Explanation:

because the heat of engine cause a gas

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An element has 9 protons, 10 neutrons, and 11 electrons. What is the name of the element?
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Which indicator would show a pH change from 6 to 7?
Blababa [14]

Answer:

Phenol red indicator.

Explanation:

  • Phenol red indicator is an organic dye which works as an indicator in the pH range (6.8 - 8.4) for acid-base reactions.

<em>The color in acidic solutions is yellow and in basic solution is red.</em>

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_______ is the cause of most ocean surface currents. A) Gravity B) The moon C) The wind D) Earth's orbit
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C)the wind

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4 years ago
What is the amount of heat required to raise the temperature of 200.0 g of aluminum by 10°C? (specific heatof aluminum = 0.21 ca
ELEN [110]

Answer:

We need 420 cal of heat

Explanation:

Step 1: Data given

Mass of the aluminium = 200.0 grams

Temperature rises with 10.0 °C

Specific heat of aluminium = 0.21 cal/g°C

Step 2: Calculate the amount of heat required

Q =m * c* ΔT

⇒with Q =  the amount of heat required= TO BE DETERMINED

⇒with m = the mass of aluminium = 200.0 grams

⇒with c = the specific heat of aluminium = 0.21 cal/g°C

⇒with ΔT = the change of temperature = 10.0°C

Q = 200.0 grams * 0.21 cal/g°C * 10.0 °C

Q = 420 cal

We need 420 cal of heat (option 2 is correct)

3 0
3 years ago
PLEASE NO FAKE ANSWERS!! Chemistry!!! Please will give brainliest !! Show work
Drupady [299]

When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.

<h3>What is Limiting reagent ?</h3>

Limiting reagents are the substances that are completely consumed first in a chemical reaction.

Given ;

  • Amopunt of Zn : 1 mole
  • Amount of O₂ : 2 mole

Given equation ;

2Zn + O₂ --> 2ZnO

As according to given chemical equation,

2 moles Zn of reacts with 1 mole of O₂ to produce 2 moles of ZnO.

Therefore,

1 mole of Zn will require 0.5 mole of O₂.

But,

the given amount of O₂ is 2 mole which is excess

Hence,

Zn here will act as the Limiting reagent, According to which the amount of product formed will be decided.

Therefore,

If 2 mole Zn produces : 2 moles of ZnO (According to given balanced equation)

Thus,

1 mole of Zn will produce = 2/2 x 1

                                          = 1 mole of ZnO

Hence, When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.

Learn more about Limiting reagent here ;

brainly.com/question/11848702

#SPJ1

3 0
2 years ago
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