Answer: 21.21 meters
Step-by-step explanation:
Hi, to answer this, first we have to calculate the circumference (C) of the wheel:
C = π x diameter
Replacing with the values given:
C = π x 45 = 141.37 cm
Then we multiply it by the number of revolutions:
141.37 x 15 = 2,120.6 cm
Since
1 cm = 0.01 m
2,120.6 x 0.01 = 21.21 meters
Feel free to ask for more if needed or if you did not understand something.
The volume of the cube that perfectly fits an 18 ft³ pyramid is calculated as (C) 54 ft³.
<h3>
What is a cube?</h3>
- A cube is a three-dimensional solid object with six square faces, facets, or sides, three of which meet at each vertex.
- The cube is one of the five Platonic solids and the only regular hexahedron.
- It has six faces, twelve edges, and eight vertices.
To find the volume of the cube that perfectly fits an 18 ft³ pyramid:
We have been provided that:
- 18 cubic feet is the volume of the pyramid.
- Now, in order for this pyramid to fit exactly into a cube, the base of the pyramid must be square, and the height of the pyramid must be equal to the height of the cube.
- We can conclude from this that the volume of a cube equals three times the volume of a pyramid.
- So, the volume of the cube = 3 × 18
- The volume of Cube = 54 ft³
Therefore, the volume of the cube that perfectly fits an 18 ft³ pyramid is calculated as (C) 54 ft³.
Know more about a cube here:
brainly.com/question/1972490
#SPJ4
The correct question is given below:
The volume of a pyramid that fits exactly inside a cube is 18 cubic feet. what is the volume of the cube?
(A) 6 cubic feet
(B) 18 cubic feet
(C) 54 cubic feet
(D) 72 cubic feet
Answer:
q*2=14 hope that this helped
Step-by-step explanation:
since product commonly mean multiplication, then you would have to make sure that q is multiplied to 2 and then provide the actual "product" of your expression or you could also just put 2q.
Answer:
Option D is correct ...
Step-by-step explanation:
because f(x) is defined on x<0 which is only possible in log(-x)
Only one line can pass through 2 points.