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k0ka [10]
3 years ago
7

Which sequence below represents an exponential sequence A.) {2,6,10,14,18,...} B.) {3,5,9,16,24,...} C.) {4,8,24,96,...} D.) {25

6,64,16,4,...}
Mathematics
1 answer:
denis-greek [22]3 years ago
6 0

Answer:

  D.)  {256,64,16,4,...}

Step-by-step explanation:

Look for the sequence in which adjacent terms are related by a common ratio.

  A. 10/6 ≠ 6/2

  B. 9/5 ≠ 5/3

  C. 8/4 ≠ 24/8

  D. 64/256 = 16/64 = 4/16 = 1/4 . . . . this exponential sequence has a common ratio of 1/4

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WHAT IS THE PRODUCT OF: 7.21 x 4.2<br> PLEASE--
lesantik [10]
<h3><u>QU</u><u>ESTION</u><u>:</u></h3>

WHAT IS THE PRODUCT OF: 7.21 x 4.2

PLEASE--

<h3>SOLUTION AND ANSWER:</h3>

\:  \:  \:  \:  \sf7.2 \: 1 \\ \sf \times \:  \:  \:  \:  4.2 \\ \:  \:    \sf \overline{1 \: 4 \: 4 \: 2}  \\  \sf +  \: 2 \: 8 \: 8 \: 4 \: 0 \:  \:  \:  \:  \:    \\  \sf \overline{ \orange{3 \: 0.2 \: 8 \: 2}}

THEREFORE, <em><u>30.282</u></em> IS THE PRODUCT

HOPE THIS HELP YOU! HAVE A NICE DAY!

~kimtaetae92~

NOTE: Kindly see this answer from brainly app if you are in web to see the displayed formats here.

7 0
2 years ago
The _____ in the hundreds place has a value ____ times as great as the _____ in the _____ place. 440
solong [7]

Answer:

The 4 in the hundreds place has a value 10 times as great as the 4 in the tens place.

Step-by-step explanation:

440 = 400 + 40 + 0

the hundreds place is worth 400 here

it is worth 10x the tens place (40 here)

5 0
3 years ago
Calculate δe, if q= 0.769 kj and w= -860 j .
Andreyy89
<span>Best Answer: 1) Q is positive therefore the process is endothermic. .769kj+-.810kj=-.041kj 2) Heat is released meaning it is exothermic. -66.9kj+45=-21.9kj 3) 7.29kj. Endothermic.</span>
7 0
3 years ago
What is the answer and how did you work it out
Anna71 [15]

Answer: b

Step-by-step explanation:

10 x 10= 100

15 x 10= 150

100+150= 250

8 0
3 years ago
What is the sum of the numbers in the series? 15 + 11 + 7 + . . . + (–129)
babymother [125]
Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109


Using AP, T(n)=15+11+7+....-129
T(n)=19-4n  => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
3 0
3 years ago
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