Given:
Equation of line
.
To find:
The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.
Solution:
The given equation of line can be written as

Slope of line is



Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is


![[\because m_1=\dfrac{7}{4}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20m_1%3D%5Cdfrac%7B7%7D%7B4%7D%5D)
Now, the slope of perpendicular line is
and it goes through (-21,2). So, the equation of line is






Therefore, the required equation in slope intercept form is
.
By evaluating the quadratic function, we will see that the differential quotient is:

<h3>
How to get (f(2 + h) - f(2))/h?</h3>
Here we have the quadratic function:

Evaluating the quadratic equation we get:

So we need to replace the x-variable by "2 + h" and "2" respectively.
Replacing the function in the differential quotient:

If we simplify that last fraction, we get:

The third option is the correct one, the differential quotient is equal to 8 + 4.
If you want to learn more about quadratic functions:
brainly.com/question/1214333
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Answer:
i think it is c sorry if wrong
Step-by-step explanation:
Use the substitution method for y=0
(40,0)
y=0
0=0
Answer: (40,0) It does make the equation y=0 true