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Explanation:
rbrhrhyhggggsdffffffffffv
In the compound iodine heptafluoride: (hints: write out the molecular formula of this compound before answering the question. Also be sure you clearly understand the concepts of charge, oxidation numbers, how to determine charge and oxidation numbers, and - most important of all! - the similarities and the differences between charges and oxidation numbers)
<u>Each fluorine atom has a charge of 1</u>
<h3>What is
iodine heptafluoride?</h3>
The interhalogen compound iodine heptafluoride, often known as iodine(VII) fluoride or iodine fluoride, has the chemical formula IF7. As anticipated by VSEPR theory, it exhibits a unique pentagonal bipyramidal structure. The molecule is capable of undergoing the Bartell process, a pseudorotational rearrangement that is similar to the Berry mechanism but for a heptacoordinated system. It produces colorless crystals that melt at 4.5 °C and have a very narrow liquid range with a boiling point of 4.77 °C. The dense mist has an unpleasant, musty smell. The molecule is symmetrical with D5h. suggestion
To learn more about iodine heptafluoride from the given link:
brainly.com/question/28200374
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The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.
The solubility of a substance in water is in accordance with the solubility rules. It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.
Now, we will consider each reaction individually to decode whether or not a precipitate is possible.
- In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
- In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
- In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g) + NaBr(aq) + H2O(l), a precipitate is not formed here.
Learn more: brainly.com/question/11969651
