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vichka [17]
3 years ago
14

water decomposes in an evacuated 2.00L container. If you started with 20.0 grams of water, determine the total resulting pressur

e of the two product gases if the reaction happens at 25°C.
Chemistry
1 answer:
Deffense [45]3 years ago
5 0

Resulting pressure is 13.6 atm.

<u>Explanation:</u>

Using Ideal gas equation, we can find the pressure of the gases formed in the reaction.

PV = nRT

Number of moles, n = given mass / molar mass = 20 g / 18 g/mol

                           = 1.11 moles

Volume, V = 2 L

Temperature, T = 25°C + 273 = 298 K

R = gas constant = 0.08206 L atm K⁻¹ mol⁻¹

P = nRT/V

 = 1.11×0.08206 ×298 / 2

 = 13.6 atm  

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Ag2S + Al(s) = Al2S3 + Ag(s) (unbalanced)
Dovator [93]

Answer:

1. 0.97 V

2. Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/Ag_(_s_)

Explanation:

In this case, we can start with the <u>half-reactions</u>:

Ag^+~_(_a_q_)->~Ag_(_s_)

Al_(_s_)~->~Al^+^3~_(_a_q_)

With this in mind we can <u>add the electrons</u>:

Ag^+~_(_a_q_)+~e^-~->~Ag_(_s_)  <u>Reduction</u>

Al_(_s_)~->~Al^+^3~_(_a_q_)+~3e^-~ <u>Oxidation</u>

The reduction potential values for each half-reaction are:

Ag_2S~+~e^-~->~Ag_(_s_)~+~S^-^2~_(_a_q_) - 0.69 V

Al^+^3~_(_a_q_)+~2e^-~->~Al_(_s_) -1.66 V

In the aluminum half-reaction, we have an oxidation reaction, therefore we have to <u>flip</u> the reduction potential value:

Al_(_s_)~->~Al^+^3~+~2e^-~ +1.66 V

Finally, to calculate the overall potential we have to <u>add</u> the two values:

1.66 V - 0.69 V = <u>0.97 V</u>

For the second question, we have to keep in mind that in the cell notation we put the anode (the oxidation half-reaction) in the left and the cathode (the reduction half-reaction) in the right. Additionally, we have to use "//" for the salt bridge, therefore:

Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/~Ag_(_s_)

I hope it helps!

3 0
4 years ago
8
Roman55 [17]

Answer:

305 litres of NO gas will be produced from 916 L of NO₂

Explanation:

Given the balanced equation of the chemical reaction as follows:

3 NO₂ (g) + H₂O( l) —— 2 HNO₃ (l) + NO (g)

Under standard conditions, 3 moles of No₂ will react with 1 mole of water to produce 1 mole of NO gas.

Molar volume of a gas at STP is 22.4 L

Number of moles of NO₂ gas present in 916 L = 916/22.4 = 40.893 moles of NO₂ gas

From the mole ratio of NO₂ to NO in the equation of reaction,

Number of moles of NO that will be produced = 1/3 × 40.893 moles = 13.631 moles of NO gas

Volume of 13.631 moles of NO gas = 13.631 × 22.4

Volume of NO gas produced = 305.334L

Therefore, Volume of NO gas produced from the reaction of 916 L of NO₂ with water = 305 L

5 0
3 years ago
I AM GETTING TIMED! PLEASE HELP ME!!
Elena L [17]

Explanation:

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5 0
3 years ago
Since the groups and periods of the Periodic Table are directly correlated,
Anna11 [10]

Answer:

<h2>All Group 1 metals form halides that are white solids at room temperature. The melting point is correlated to the strength of intermolecular</h2>
7 0
3 years ago
A person's heartbeat is 73 beats per minute. If his heart beats 3.1e9 times in a lifetime, how long does the person live?
tiny-mole [99]

Answer:  The person lived for 80.66 years.

Explanation:

Heart beat of the person = 73 beat /min

Number of total heart beats = 3.1\times 10^{9}

Life span of the person : \frac{\text{Total heart beats of the person}}{\text{Heart beat per minute}}=\frac{3.1\times 10^{9} beats}{73 beat/min}

1 year =525600 mins

Life span = 0.0424\times 10^{9} min=80.66 years

The person lived for 80.66 years.

7 0
3 years ago
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