Answer:
[CH₃COOH] = 17.4 M
Explanation:
Acetic acid → CH₃COOH
Molar mass → 60 g/mol
99.5% is percent by mass concentration. It means that 99.5 grams of solute are contained in 100g of solution.
Density → 1.05 g/mL. This data is always referred to solution, not solute!.
We determine solution's volume:
1.05 g/mL = 100 g / V → V = 100 g /1.05 g/mL → 95.2 mL
Now we know, that 99.5 g of acetic acid are contained in 95.2 mL
Let's convert to mmoles → 99.5 g / 60 g/mol = 1.66 moles
We convert solution's volume to L → 95.2 mL . 1L / 1000 mL = 0.0952 L
M (mol/L) = 1.66 mol / 0.0952 L = 17.4 M
Explanation:
here's the answer to your question
Answer:
The mole is the SI unit for amount of a substance.
Explanation:
Just like the dozen and the gross, it is a name that stands for a number. There are therefore 6.02 × 10 23 water molecules in a mole of water molecules.
Answer:
0.321M would be the concentration of the final solution
Explanation:
In the problem, you are decreasing the concentration of a solution (The stock solution) by the addition of more solvent (This process is known as dilution).
You are increasing the volume of the solution from 15mL to 700mL, that means the solution <em>is diluted:</em>
700mL / 15mL = 46.67 times
Now, to know the concentration of a final solution we need to take the concentration of the stock solution. <em>Assuming the stock solution is 15M:</em>
15M / 46.67 =
<h3>0.321M would be the concentration of the final solution</h3>
Nuclear energy = nuclear bobm = nuclear war = bad ;(
