When 20 ml of 0.1 M HCl is mixed with 20

Which properties, physical or chemical, were most useful in identifying the mystery powder? Explain your answer.

r-ruslan [8.4K]

The answer depends on what substances you were testing, but here are some ideas.

If all of them were white as in the typical experiment, then color is not very useful. If you were allowed to taste them, then a salty taste would be a helpful clue. If the textures were different, some crystals, like salt or sugar and others powdery, like flour or cornstarch, those properties would be helpful. If some dissolved in water,...

5 0

3 years ago

What is the formula for hexaboron tetrabromide

Sveta_85 [38]

Answer:

The formula for the compound isB6Br7

6 0

3 years ago

A student was asked to determine the concentration of ammonia, a volatile substance used in the clinical setting as a respiretor

UNO [17]

This question is describing two chemical equations whereby the concentration of ammonia has to be determined. The first reaction is between 25.00 mL of ammonia and 50.00 mL of 0.100-M HCl whose excess was neutralized with 21.50 mL of 0.050-M Na₂CO₃ and thus, the concentration ammonia in the cloudy solution was determined as 0.114 M.

First of all we need to go over the titration of the excess HCl with Na₂CO₃ by writing the chemical equation it takes place when they react:

$2HCl+Na_2CO_3\rightarrow 2NaCl+CO_2+H_2O$

Whereas the mole ratio of HCl to Na₂CO₃ is 2:1 and the volume of the HCl leftover is determined as follows:

$V_{HCl}^{leftover}=\frac{2*0.050M*21.50mL}{0.100M} =21.5mL$

Next, we infer that the consumed volume of HCl by the ammonia solution was:

$V_{HCl}^{consumed}=50.00mL-21.50mL=28.5 mL$

Then, we write the chemical equation that takes place between ammonia and HCl:

$HCl+NH_3\rightarrow NH_4Cl$

Whereas the mole ratio is now 1:1, which means that the concentration of ammonia was:

$M_{NH_3}=\frac{28.5mL*0.100M}{25.00mL}\\\\ M_{NH_3}=0.114M$

Learn more:

(Titration) brainly.com/question/15687419
(Titration) brainly.com/question/25328286

8 0

2 years ago

What is the concentration of chloride ions in a solution formed by mixing 150. mL of a 1.50 M NaCl solution with 250. mL of a 0.

joja [24]

Here, we apply a mass balance:
Moles of chloride ions in final solution = sum of moles of chloride ions in added solutions

We must also not that each mole of sodium chloride will release one mole of chloride ions, while each mole of magnesium chloride will release two moles of chloride ions.
Moles = concentration * volume
Moles in final solution = moles in NaCl solution + moles in MgCl₂ solution
C * (150 + 250) = 1.5 * 150 + 2 * 0.75 * 250
C = 1.5 M

The final concentration is 1.5 M

4 0

3 years ago

10. Almost all of the atoms that you encounter have (stable/unstable) nuclei.

Montano1993 [528]

Answer:

stable, because there is always an equal amount of force surrounding the atom

3 0

3 years ago