Answer:
a. 
b. K = 192.9
c. Products are favored.
Explanation:
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a. In this case, according to the unbalanced chemical reaction we need to balance HCl as shown below:
In order to reach 2 hydrogen and chlorine atoms at both sides.
b. Here, given the concentrations at equilibrium and the following equilibrium expression, we have:
![K=\frac{[HCl]^2}{[H_2][Cl_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BHCl%5D%5E2%7D%7B%5BH_2%5D%5BCl_2%5D%7D)
Therefore, we plug in the data to obtain:
c. Finally, we infer that since K>>1 the forward reaction towards products is favored.
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Iodine 131 is a radioisotope with a very short half-life of 8.02 days, making it highly radioactive. Frequently used in small doses in thyroid cancers therapies, it is also one of the most feared fission products when accidentally released into the environment. Radiotoxicity of iodine 131.
First find the number of moles of sulfur using dimensional analysis with avogadro’s number as the conversion factor. 4.2*10^24 atoms * (1 mol/6.022*10^23 atoms) = 7.0 mol sulfur. The molar mass of sulfur is 32.06 g/mol, which is found on the periodic table as sulfur’s (S) atomic weight. Use dimensional analysis again with the molar mass of sulfur as the conversion factor. 7.0 mol * 32.06 g/mol = 224.42 g sulfur. Since the problems gives us two significant figures, round the mass of sulfur to 220 grams, or 2.2 * 10^2 g.
Answer:
the molar mass of propane (c3H8) is
12*3+1*8
=36+8=44
