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kozerog [31]
4 years ago
9

Which set of side lengths form a right triangle

Mathematics
2 answers:
earnstyle [38]4 years ago
7 0
There are a few possibilities, you could have 60 degrees 30 degrees and 90 degrees, for one triangle those added up equal 180 which is needed to make a right triangle. Another possibility would be 45 degrees 45 degrees 90 degrees, those added up equals to 180 degrees. :D
professor190 [17]4 years ago
4 0
I would think C. The normal theorem to use on this is a^2 + b^2 = c^2. This only works for choice c. 6^2=36. 8^2=64 10^2=100. 36+64=100. That makes C correct.
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What is the value of y in this system of equations: 3x + y = 9 y = –4x + 10 ?
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<span>3x + y = 9 (I)
</span><span>y = –4x + 10 (II)
------------------------
</span>\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.

Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
simplify by (-1)
</span>\left \{ {{3x + y = 9.(-1)} \atop {4x + y = 10 }} \right.<span>

-------------------------
</span>\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right.     &#10;
<span>
-------------------------
</span>\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.<span>

-----------
</span>\boxed{x = 1}<span><span>

</span></span><span>Substitute in equation (I) to find the value of "Y".

</span>3x + y = 9 (I)
3*(1) + y = 9
3 + y = 9
y = 9 - 3
\boxed{y = 6}

Answer:
\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}

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