The answer is 0.975 L
Volume = mol/Molarity
We have molarity (0.788 M) and we need mol and volume. Let's first calculate number of moles of CaCl2 in 85.3 g:
Molar mass of CaCl2 is sum of atomic masses of Ca and Cl:
Mr(CaCl2) = Ar(Ca) + 2Ar(Cl) = 40 + 2 * 35.45 = 40 + 70.9 = 110.9 g/mol
So, if 110.9 g are in 1 mol, 85.3 g will be in x mol:
110.9 g : 1 mole = 85.3 g : x
x = 85.3 g * 1 mole / 110.9
x = 0.769 moles
Now, calculate the volume:
V = 0.769/0.788
V = 0.975 L
Answer:
The molar mass of
is 342.145 g/mol
Explanation:
The molar mass is stated as the “mass per unit amount of substance”of a given chemical compound
is Aluminium sulphate. They easily dissolve in water. It is primarily used as a 'coagulating agent' in the drinking water purification and also in waste and sewage water treatment plants,
We know,
Atomic weight of Aluminium = 26.981
Atomic weight of Sulphur= 32.065
Atomic weight of Oxygen = 15.9994
Now molar mass of
(Aluminium sulphate) is
=>2(26.981)+3(32.065+4(15.999))
=>53.962 +3(32.065+63.996)
=>53.962+3(96.061)
=>53.962+288.183
=>342.145
they move around and eventually come and join to make a solid
Answer:
C) SN2 and E2
Explanation:
For this question, we have analyzed the <u>substrate</u> and the <u>base/nucleophile</u>. The substrate, in this case, is 1-iodohexane and the base/nucleophile is potassium tert-butoxide.
<u>Substrate</u>
<u />
In the 1-iodohexane the iodide "I" is bonded to a primary carbon (carbon 1). Therefore we will have a <u>primary substrate</u>. If we have a primary substrate an Sn1 can not take place. We can not have a <u>primary carbocation</u> due to this instability. So, we can disccard options A) and B).
<u>Base/nucleophile</u>
<u />
In the potassium tert-butoxide we have an ionic compound. A positive charge is placed in the potassium atom a negative charge is placed in the oxygen of the ter-butoxide ion. So, we will have a <u>strong base</u> (a molecule with the ability to remove electrons) and a <u>strong nucleophile</u> (a molecule with ability to bond with an electrophile). With all this in mind, w<u>e can not have an E1 reaction</u>.
With both analyses, the answer is C).
See figure 1
I hope it helps!