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n a certain city, electricity costs $0.18 per kW·h. What is the annual cost for electricity to power a lamp-post for 6.50 hours

Bond [772]

a)

Consumption of power in one day = $100 W \times 6.5 h = 650 Wh$

Consumption of power in one year = $100 W \times 6.5 h\times 365 = 237250 Wh$

Since, $1 Wh = 0.001 kWh$ . So,

$237250 Wh = 237.25 kWh$

Given that $1 kWh$ = $$0.18$

So, for $237.25 kWh$ :

$237.25 kWh\times$ $ $0.18/ kWh$ = $ $42.705$

Hence, the annual cost is $ $42.705$ .

b)

Consumption of power in one day = $25 W \times 6.5 h = 162.5 Wh$

Consumption of power in one year = $25 W \times 6.5 h\times 365 = 59312.5 Wh$

Since, $1 Wh = 0.001 kWh$ . So,

$59312.5 Wh = 59.3125 kWh$

Given that $1 kWh$ = $$0.18$

So, for $59.3125 kWh$ :

$59.3125 kWh\times$ $ $0.18/ kWh$ = $ $10.676$

Hence, the annual cost is $ $10.676$ .

6 0

3 years ago

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What is the net ionic equation for AgNO3 (aq) + K2SO4 (aq)

lesya [120]

2Ag +(aq) + SO4 2-(aq)----->Ag2SO4 (s)

4 0

3 years ago

The addition of which substance will decrease the solubility of AgNO3 in water?

sertanlavr [38]

3 is correct because the .1 moles of the NO3 will be better option to decrease the solubility of the Silver Nitrate.

5 0

3 years ago

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The process of generating electricity from dams and nuclear power plants is very different, but some of the energy transformatio

Alexxx [7]

Answer:

Kinetic energy to mechanical energy, and mechanical energy to electrical energy.

Explanation:

From the Law of conservation of Energy, which state that energy can neither be created nor destroyed but can be transformed from one form to another. Energy transformation is essential in science and technology, in the process of generating electricity from dams and nuclear power plants

some of the energy transformations are the same, the energy transformations occur in both dams and nuclear power plants is Kinetic energy to mechanical energy, and mechanical energy to electrical energy. Kinectic energy is the energy in motion which means the dams is a running water and posses a Kinectic energy then it's is been convert to mechanical energy (which is the macroscopic energy) then to electrical energy by producing light.

3 0

2 years ago

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Determining Density and Using Density to Determine Volume or Mass

Shalnov [3]

corrected question:

Determining Density and Using Density to Determine Volume or Mass

(a) Calculate the density of mercury if 1.00 × 10 g occupies a volume of 7.36 cm³

(b) Calculate the volume of 65.0 g of liquid methanol (wood alcohol) if its density is 0.791 g/mL.

(c) What is the mass in grams of a cube of gold (density = 19.32 g/cm) if the length of the cube is 2.00 cm?

(d) Calculate the density of a 374.5-g sample of copper if it has a volume of 41.8 cm³ A student needs 15.0 g of ethanol for an experiment. If the density of ethanol is 0.789 g/mL, how many milliliters of ethanol are needed? What is the mass, in grams, of 25.0 mL of mercury (density = 13.6 g/mL)?

Answer:

density = $\frac{mass}{volume}$

ρ=m/v ,m=ρv, v=m/ρ

(a)m=1*10g , v=7.36cm³

ρ=10/7.36 =1.36g/cm³

(b) m=65g, ρ=0.791 g/mL.

v= 65/0.791 =82.17g/mL

(c) ρ=19.32g/cm³, l=2cm, v=l³=8cm³

m=19..32*8=154.56g/cm³

(d) mass of copper=374.5g , v=41.8cm³

ρ=374.5/41.8 =8.96g/cm³

mass of ethanol=15g, density of ethanol=0.789g/mL

v=15/0.789 =19.01mL

volume of mecury=25mL, density of mercury=13.6g/mL

m=25*13.6=340g

4 0

3 years ago