Answer:
Iodine have higher atomic size than tellurium because of the presence of more number of protons and lower atomic mass than tellurium because of the presence of lower number of neutrons.
Explanation:
Atomic number of an element is the number of the protons present in the element.
Atomic mass is the sum of a protons and the neutrons which are present in the nucleus of the atom.
Iodine has higher atomic number than tellurium because it has more number of protons than the tellurium.
On the other hand, iodine has lower atomic mass than tellurium because it has less number of neutrons in its core.
The atomic number increases moving left to right across a period and subsequently so does the effective nuclear charge. Therefore, moving left to right across a period the nucleus has a greater pull on the outer electrons and the atomic radii decreases.
Answer : Option 1) The true statement is each carbon-oxygen bond is somewhere between a single and double bond and the actual structure of format is an average of the two resonance forms.
Explanation : The actual structure of formate is found to be a resonance hybrid of the two resonating forms. The actual structure for formate do not switches back and forth between two resonance forms.
The O atom in the formate molecule with one bond and three lone pairs, in the resonance form left with reference to the attached image, gets changed into O atom with two bonds and two lone pairs.
Again, the O atom with two bonds and two lone pairs on the resonance form left, changed into O atom with one bond and three lone pairs. It concludes that each carbon-oxygen bond is neither a single bond nor a double bond; each carbon-oxygen bond is somewhere between a single and double bond.
Also, it is seen that each oxygen atom does not have neither a double bond nor a single bond 50% of the time.
Answer:
they will eat a lot of fish and make other animals go hungry
Explanation:
logic