Question

Leonard adds 5 grams of sugar to 1 liter of water to make one sugar solution. Then he adds 10 grams of sugar to 1 liter of water to make another sugar solution. Which statement correctly compares these solutions?

Answer 1

Answer:

See explanation below

Explanation:

There are many statements and ways to compare both solutions, but the commons one are concentration or molarity, and %m/V.

Both of these statements are valid to compare both solutions, however, molarity is the best to use because with a single number, we can see which solution is more concentrated.

To calculate the molarity of any solution we use the following expression:

M = n/V

n: number of moles of solute.

V: volume of solution in liter.

Now, as the solvent of the solution is water, and the solute is a solid, the volume of solution will be the same volume of the solvent.

The common sugar is the sucrose, and the molecular formula of this is C12H22O11, the molar mass is 342.3 g/mol.

With this, we can calculate the moles:

n = m/MM

n₁ = 5/342.3 = 0.0146 moles

n₂ = 10/342.3 = 0.0292 moles

Now, it's time to see the concentration of each solution:

M₁ = 0.0146 / 1 = 0.0146 M

M₂ = 0.0292 / 1 = 0.0293 M

With this we can conclude that solution 2 is more concentrated than solution 1. In other words M₂ > M₁