Answer:
3.16 × 
W/
Explanation:
β(dB)=10 × 
=
W/
β=55 dB
Therefore plugging into the equation the values,
55=10 ![log_{10}(\frac{I}{ [tex]10^{-12}](https://tex.z-dn.net/?f=log_%7B10%7D%28%5Cfrac%7BI%7D%7B%20%5Btex%5D10%5E%7B-12%7D)
})[/tex]
5.5= })[/tex]
= 
316227.76×= I
I= 3.16 × W/
Answer:
(a) Heat transfer to the environment is: 1 MJ and (b) The efficiency of the engine is: 41.5%
Explanation:
Using the formula that relate heat and work from the thermodynamic theory as:
solving to Q_out we get:
this is the heat out of the cycle or engine, so it will be heat transfer to the environment. The thermal efficiency of a Carnot cycle gives us: 
where T_Low is the lowest cycle temperature and T_High the highest, we need to remember that a Carnot cycle depends only on the absolute temperatures, if you remember the convertion of K=°C+273.15 so T_Low=150+273.15=423.15 K and T_High=450+273.15=723.15K and replacing the values in the equation we get:
Answer:
<h2>7.21 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 2.060 × 3.5
We have the final answer as
<h3>7.21 J</h3>
Hope this helps you
Answer:
that technician A is right
Explanation:
The test lights are generally small bulbs that are turned on by the voltage and current flowing through the circuit in analog circuits, these two values are high and can light the bulb. In digital circuits the current is very small in the order of milliamps, so there is not enough power to turn on these lights.
From the above it is seen that technician A is right
Answer:
0.08821 kgm²
Explanation:
f = Frequency = 1.7 Hz
m = Mass of lower leg = 5.7 kg
d = Distance of center of mass = 18 cm
g = Acceleration due to gravity = 9.81 m/s²
I = Moment of inertia
Frequency is given by
The moment of inertia of the lower leg is 0.08821 kgm²
