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blsea [12.9K]
4 years ago
8

A bicycle traveled 150 meters west from point A to point B. Then it took the same route and came back to point A. It took a tota

l of 2 mins for the bicycle to return to point A. What is the average speed and average velocity of the bicycle?
A.
The average speed is 2.5 meters/second, and the average velocity is
2.5 meters/second east.

B.
The average speed is 0 meters/second, and the average velocity is
2.5 meters/second east.
C.
The average speed and average velocity are both 0 meters/second,
D.
The average speed is 2.5 meters/second, and the average velocity is
0 meters/second​
Physics
1 answer:
Katen [24]4 years ago
6 0
B i really
hope i helped
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For both resonance curves and Fourier spectra, amplitude is plotted vs frequency, but these two types of plots are not the same.
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he peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.

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A glass tube 1.50 meters long and open at one end is weighted to keep it vertical and is then lowered to the bottom of a lake. W
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Complete Question

 The complete question is shown on the first uploaded image  

Answer:

The total pressure is  P_T  = 10.79*10^{5} N/m^2

The temperature at the bottom is T_b  = 284.2 \ K

Explanation:

From the question we are told that

    The length of the glass tube is  L  = 1.50 \ m

      The length of water  rise at the bottom of the lake  d = 1.33 \ m

     The depth of the lake is  h =  100 \ m

     The air temperature is T_a   =  27 ^oC =  27 +273 =  300 \ K

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substituting values

               P_T  = 1.01*10^{5}  + 998 * 9.8 * 100

               P_T  = 10.79*10^{5} N/m^2

According to ideal gas law

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             P_a V_a =  nRT_a

Where is the volume of

             P_a *A * L  = nRT_a

 At the bottom of the lake  

           P_T V_b  =  nRT_b

Where V_b is the volume of the glass tube not covered by water at bottom

          and  T_b i the temperature at the bottom

  So the ratio between the temperature  at the surface to the temperature at the bottom is mathematically represented as

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substituting values

           \frac{T_b}{27}  =  \frac{0.133  * 10.79 *10^5}{1.01 *10^{5} * 1.5}

   =>     T_b  = 284.2 \ K

           

       

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