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il63 [147K]
3 years ago
9

Consider the hypothetical observation "a planet beyond Saturn rises in west, sets in east." This observation is not consistent w

ith a Sun-centered model, because in this model __________.
a. there are no planets beyond Saturn
b. all objects in space must orbit the Sun in the same direction
c. planets beyond Saturn must orbit the Sun more slowly than closer-in planets
d. the rise and set of all objects depends only on Earth’s rotation
Physics
1 answer:
pickupchik [31]3 years ago
5 0

This observation is not consistent with a Sun-centered model, because in this model "the rise and set of all objects depends only on Earth’s rotation".

<u>Answer:</u> Option D

<u>Explanation:</u>

Copernican heliocentrism, the astronomical model's title which was created by Nicolaus Copernicus and released in 1543. This model placed the Sun in motionless position near the Universe's center, with Earth and the planets of other which orbiting it in a circular orbits, altered by epicycles, and also at constant speeds.

Out of several planets in a determined order the Earth orbits around a stationary sun having three motions like annual revolution, daily rotation, and its axis is tilted annually. The planets' retrograde motion is understood by motion from the Earth.

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A 0.015 kg marble moving to the right at 0.225 m/s makes an elastic head-on collision with a 0.030 kg shooter marble moving to t
bonufazy [111]

Answer:

0.09 m/s to the right

Explanation:

The principle of conservation of linear momentum states that in a system of colliding objects, the total momentum before collision is equal to the total momentum after collision, provided there is no external force.

The total momentum, in this question, is the sum of the momentum of the the two marbles. We assume velocity to the right is positive while to the left is negative. Thus, total initial momentum is

P_i = 0.015\times0.225+ 0.030 \times(-0.180) = 0.002025

After collision, the first marble goes left. Let the velocity of the other marble be v. Then we have

P_f = 0.015\times(-0.315) + 0.030v = 0.030v - 0.004725

Equating both momenta,

P_i = P_f

0.002025 = 0.030v - 0.004725

v = 0.09 \text{ m/s}

Hence, the larger goes right with a velocity of 0.09 m/s (since it has a positive sign).

4 0
3 years ago
Suppose that the strings on a violin are stretched with the same tension and each has the same length between its two fixed ends
lesya692 [45]

Answer:

0.00384 kg/m

Explanation:

The fundamental frequency of string waves is given by

f=\frac{1}{2L}\sqrt{\frac{F}{\mu}}

For some tension (F) and length (L)

f\propto\frac{1}{\mu}

Fundamental frequency of G string

f_G=196\ Hz

Fundamental frequency of E string

f_E=659.3\ Hz

Linear mass density of E string is

\mu_E=3.4\times 10^{-4}\ kg/m

So,

\frac{F_G}{F_E}=\sqrt{\frac{\mu_E}{\mu_G}}\\\Rightarrow \frac{F_G^2}{F_E^2}=\frac{\mu_E}{\mu_G}\\\Rightarrow \mu_G=3.4\times 10^{-4}\times \frac{659.3^2}{196^2}\\\Rightarrow \mu_G=0.00384\ kg/m

The linear density of the G string is 0.00384 kg/m

4 0
3 years ago
To extend the electrical system between the main panel and the secondary panel, the electricians used
umka21 [38]

Answer:

i think A

Explanation:

7 0
3 years ago
Durante un intento juego de croquet, una bola de 0.52 kg en reposo sobre el cesped es golpeada por un mazo con una fuerza promed
Romashka [77]

Answer: 2.63 m/s

Explanation:

The question in english is written below:

During an attemp of croquet game, a 0.52 kg ball at rest on the grass is hit by a mallet with an average force of 190 N, if the mallet is in contact with the ball for 7.2(10)^{-3} s,  Whay is the speed of the ball just after being hit?

According to Newton's second law of motion, the force F exerted on an object is directly proportional to its mass m and acceleration a:

F=m.a (1)

On the other hand, acceleration is defined as the variation of velocity V in time t:

a=\frac{V}{t} (2)

Substituting (2) in (1):

F=m\frac{V}{t} (3)

Where:

F=190 N

m=0.52 kg

t=7.2(10)^{-3} s

Isolating the velocity V from (3):

V=\frac{Ft}{m} (4)

V=\frac{(190 N)(7.2(10)^{-3} s)}{0.52 kg}

Finally:

V=2.63 m/s

6 0
4 years ago
Mike walks 100 meter north, then walks 30 meters south. after this, he walks another 10 meters north.
Liono4ka [1.6K]

Answer:

The answer is 80

Explanation:

because 100-30+10 is 80

5 0
3 years ago
Read 2 more answers
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