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coldgirl [10]
3 years ago
8

Two hundred grams of liquid A is at a temperature of 100◦C. One hundred grams of liquid B is at a temperature of 0◦C. When the t

wo liquids are mixed, the final temperature is 50◦C. Which material has a higher specific heat? 1. The specific heat of A is greater than that of B. 2. The specific heat of A is great than B if its viscosity is greater. 3. The specific heats of A and B are equal. 4. The specific heat cannot be defined when fluids are mixed in this way. 5. The specific heat of B is greater than that of A. "correct"
Physics
1 answer:
Agata [3.3K]3 years ago
4 0

Answer:

The specific heat of B is greater than that of A.

Explanation:

The amount of heat lost by A is:

q = m C ΔT

q = (200 g) Ca (100°C - 50°C)

q = 10,000 Ca

The amount of heat gained by B is:

q = (100 g) Cb (50°C - 0°C)

q = 5,000 Cb

Since the heat lost by A = heat gained by B:

10,000 Ca = 5,000 Cb

2 Ca = Cb

So the heat capacity of B is double the heat capacity of A.  Answer 5.

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7 0
3 years ago
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The first few steps in deriving the quadratic formula are shown. Which best explains why is not added to the left side of the eq
bija089 [108]
The term b^2 / 4a^2 is not added to the left side of the equation, because the term that was added to the right was not either b^2 / 4 a^2.

As you can see the ther b^2 / 4a^2 that appears in the last step of the table is inside a parenthesis, which is preceded by factor a.


Then, you need to apply the distributive property to know the term that you are really adding to the right side,  i.e. you need to mulitply b^2 / 4a^2 * a which is b^2 / 4a.


That means that you are really adding b^2 / 4a to the right, so that is the same that you have to add to the left, which is what the last step of the table shows.


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6 0
3 years ago
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An airplane has a velocity of 907 km/hr westward relative to the air. If the air is moving eastward at 82 km/hr, what is the vel
Lisa [10]

Answer:

D.  825 km/hr westward

Explanation:

In order to solve the problem, we should define a positive and a negative direction for the velocities.

Let's take positive (+) as westward and negative (-) as eastward.

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2) Relative to the air, the airplane is moving westward at 907 km/h, so its velocity is v=+907 km/h

In the reference system of the ground, the velocity of the airplane will be given by the velocity of the airplane in the reference system of the air (v) plus the velocity of the reference system of the air relative to the ground (v'):

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8 0
3 years ago
Whipple is confused about the connection between the velocity and acceleration of the tennis ball. he decides to compare the vel
tamaranim1 [39]

The speed of the ball is always zero and the acceleration is always -g when it reaches the top of its motion. This is because when the ball is free, only gravity acts on it which is always downwards, hence g is the net acceleration and it is always negative. However the velocity does not direction change instantly, negative acceleration first slows down the ball with a positive velocity, until that point the ball keeps moving up, then the ball velocity becomes zero just before changing direction and becoming negative after which the ball will now go down along gravity. Hence the ball velocity is zero at the top (neither going up nor down). Mathematically this can be seen as velocity is the integration of acceleration.

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