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Vera_Pavlovna [14]
3 years ago
13

A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to

1.3 atm, and the temperature of the gas increases to 285 K.
Physics
2 answers:
erastovalidia [21]3 years ago
7 0
Would presume you are asked to find the volume, since there is no second volume.

By General Gas Law:

P₁V₁/T₁ = P₂V₂/T₂

1.6 * 168 /255 = 1.3*V₂/285

V₂ = 1.6 * 168 * 285 / (1.3*255)

V₂ = 231.095

Final volume ≈ 231 cm³
allsm [11]3 years ago
5 0

Answer: The final volume is  231cm^3

Explanation: Using ideal gas equation:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

P_1= initial pressure = 1.6 atm

V_1= initial volume = 168cm^3

T_1= initial temperature = 255 K

P_2= final pressure= 1.3 atm

V_2= final volume = ?

T_2= final temperature = 285 K

\frac{1.6\times 168}{255}=\frac{1.3\times V_2}{285}

V_2=231cm^3


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