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marissa [1.9K]
3 years ago
13

A. Draw four rays parallel to the optical axis of your mirror. Two above the optic axis and two below it.

Physics
1 answer:
Katen [24]3 years ago
6 0

Answer:

   f = q

Explanation:

In the attachment we can see a diagram of the parallel rays.

The dotted line represents the normal to the mirror surface

These rays when reflected using the constructor equation

        \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where p and q are the distance to the object and the image respectively.

Since the rays are parallel P = inf

          1 / f = 1 / inf + 1 / q

          f = q

this means that all the rays focus on one focal point.

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The initial momentum and the vertical and horizontal component
tamaranim1 [39]
Momentum = mass * velocity

p = mv

p = 1.5 kg * 40 ms^-1

p = 60 kgm/s

To find components of a vector:

px = p * cos(theta)
px = 60 * cos(30)
px = 51.96 = 52 (rounded to two significant digits)

py = p * sin(theta)
py = 60 * sin(30)
py = 30

He initial momentum is 60kgm/s
The horizontal component is 52 kgm/s
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8 0
3 years ago
Two trains are on separate but parallel tracks running east and west. One has a speed of 90 km/h, the other 80 km/h. Initially,
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4 years ago
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Answer:

a) 0.21N/C

b) counterclockwise

Explanation:

a) to find the magnitude of the electric field you can use the following formula:

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A: area of the ring = pi*r^2

E: electric field

Ф_B: magnetic flux

In the line integral you can assume E as constant. Furthermore, you calculate the change in the magnetic flux by taking into account that the time interval is 1.12/0.21=5.33s. By replacing in the formula you obtain:

\frac{\Delta \Phi_B}{\Delta t}=\frac{A(B_f-B_i)}{5.33s}=\frac{\pi(0.04m)^2(1.12T)}{5.33}=1.056*10^{-3}W/s

E\int ds=E(2\pi r)=1.056*10^{-3}W/s\\\\E=\frac{1.056*10^{-3}W/s}{\pi(0.04m)^2}=0.21\frac{N}{C}

the magnitude if the induced electric field is 0.21N/C

b) By the Lenz's law you can conclude that the current has a direction in a counterclockwise

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3 years ago
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Answer:

b

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bc

8 0
3 years ago
Michael's house is 5.0 km away from his school. How long would it take him to go ti school, riding a bus, if its velocity is 25
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Answer:

12 mins

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