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3 years ago

How would I start a science project on egg dropping

2 answers:

6 0

Find a way to slow down the egg's momentum before it hits the ground.
maybe using a spiral type object to add a subtle spin to slow it down

Rus_ich [418]3 years ago

6 0

It actually depends on how you want to go about it. If it was me in your shoes I would do it based on the time it took for the egg to drop. I would use several different type of eggs for my experiment. But first you'll halve to make your prediction, by predicting which egg would drop the fastest or which egg would take a longer amount of time to drop. To make it better you can also do it in several locations.
HOPE THIS HELPS! ^_^

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A river flows with a speed of 0.600 m/s. A student first swims upriver 0.500 km, then turns around and returns to his starting p

DerKrebs [107]

Answer:

a) 1111.0 seconds

b) 833.3 s

c) Because of proportions

Explanation:

a) Total time of round trip is the sum of time upriver and time downriver

$t_{total}=t_{up}+t_{down}$

Time upriver is calculated with the net speed of student and 0.500 km:

$t_{up}=\frac{d_{istance}}{|v_{swimmer}|} ;\\v_{swimmer}=v_{relative to river}+v_{river}=-1.2+0.6=-0.6 m/s\\t_{up}=\frac{500 m}{0.6 m/s}=833.3 s$

(Becareful with units 0.5 km= 500m) Similarly of downriver:

$t_{down}=\frac{d_{istance}}{|v_{swimmer}|} ;\\v_{swimmer}=1.2+0.6=1.8 m/s\\t_{down}=\frac{500 m}{1.8 m/s}=277.7 s$

So the sum is:

$t_{total}=1111.0s$

b) Still water does not affect student speed, so total time would be simply:

$t_{total}=\frac{1000 m}{1.2 m/s}=833.3 s$

c) For the upriver trip, student moved half the distance in half speed of the calculation in b), so it kept the same ratio and therefore, same time. So the aditional time is actually the downriver.

6 0

3 years ago

A 75 kg ball carrier is running to the right at 6.5 m/s. An 80 kg defender is chasing the ball carrier running at 7.0 m/s. The d

Sophie [7]

Answer:

3,544.375Joules

Explanation:

Kinetic energy is the energy possessed by a body by virtue of its motion, It is expressed as;

Kinetic energy = 1/2mv²

m is the mass of the body

v is the velocity

For the ball carrier;

KE = 1/2(75)(6.5)²

KE = 3168.75/2

KE = 1584.375Joules

For the defender;

KE = 1/2(80)(7)²

KE = 3920/2

KE = 1960Joules

The kinetic energy of the ball carrier/defender system BEFORE the tackle = KE for the carrier + KE for the defender

kinetic energy of the ball carrier/defender system BEFORE the tackle= 1584.375+1960 = 3,544.375Joules

7 0

2 years ago

How is the energy of the wave affected if the amplitude of the wave increases from 2 meters to 4

Alex777 [14]

Answer:

Energy of wave will increase as the energy of wave is related to the amplitude of wave

5 0

3 years ago

A 7.00 g bullet, when fired from a gun into a 1.00 kg block of wood held in a vise, penetrates the block to a depth of 8.00 cm b

Sauron [17]

Answer:

Explanation:

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5 0

2 years ago

Solubility describes the ability of a substance to evaporate and separate out true or false

sweet [91]

Solubility is a substance dissolving in a liquid. So I would say False just because of the wording here.

5 0

3 years ago

Read 2 more answers