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natima [27]
3 years ago
10

How would I start a science project on egg dropping

Physics
2 answers:
Sholpan [36]3 years ago
6 0
Find a way to slow down the egg's momentum before it hits the ground.
maybe using a spiral type object to add a subtle spin to slow it down
Rus_ich [418]3 years ago
6 0
It actually depends on how you want to go about it. If it was me in your shoes I would do it based on the time it took for the egg to drop. I would use several different type of eggs for my experiment. But first you'll halve to make your prediction, by predicting which egg would drop the fastest or which egg would take a longer amount of time to drop. To make it better you can also do it in several locations.
HOPE THIS HELPS! ^_^

You might be interested in
Help me plsssss I need. The question is confusing and so sorry if it blurry
Savatey [412]

Answer:

400Pa

Explanation:

The question asks for you to substitiute in known values into the formula to solve for pressure which is calculated through force/area

in this instance

force=300N

area=0.75m^2

substitute in the values and solve for pressure

300/0.75=pressure

pressure=400Pa (the si unit for pressure is Pa or pascal)

3 0
3 years ago
Two thin parallel conducting plates are placed 2.0 cm apart. Each plate is 2.0 cm on a side; one plate carries a net charge of 8
azamat

Gauss's law and charges of the same sign repel allows us to find the results for the questions about the charged plates are:

  • The charge inside the plates is zero.
  • The field in the middle of the plates is: E = 2.26 10⁶ N/C

<h3>Gauss's law.</h3>

Gauss's law says that the electric flux through a Gaussian surface is proportional to the charge inside it.

         Ф = ∫ E . dA = \frac{q_{int}}{\epsilon_o }

where Ф is the flux, E the electric field, A the area, q_{int} the charge inside the surface.

They indicate that we have two metallic plates with a charge of 80 μC = 80 10⁻⁶ C in each one, since the plate is metallic, the electrons are free to move in it and repel each other, therefore the ones that are farthest from each other are placed, this is concentrated on the surface of the metal plate, therefore the charge inside the surface is zero.

Let's use Gauss's law to find the electric field, we define a Gaussian surface with a cylinder base parallel to the plate, in this case the field created by the charge is parallel to the normal of the surface of the plates.

              2 E A = \frac{q_{int}}{\epsilon_o}

The two comes from the fact that the electric field is emitted towards both sides of the plate.

             

The charge density on each plate is:

              σ = q A

       

Let's substitute.

             E A = \frac{\sigma A}{2 \ \epsilon_o}

     

The electric field is a vector magnitude, so vector addition must be used, see attached for the direction of the electric field.

              R_{total} = E_1+E_2

              E_{total} = \frac{\sigma}{\epsilon_o}

Let's calculate.

The charge density.

          \sigma = \frac{q}{l^2}

          \sigma = \frac{ 80 \ 10^{-6} } { 2.0 \ 2.0}

          σ = 20 10⁻⁶ C

The total electric field.

          E = \frac{20 \ 10^{-6} }{8.85 \ 10^{-12} }

          E = 2.26 10⁶ N/C

In conclusion, using Gauss's law and that charges of the same sign repel each other, we can find the result for the questions about the charged plates:

  • The charge inside the plates is zero.
  • The field in the middle of the plates is: E = 2.26 10⁶ N/C

Learn more about Gauss's law here: brainly.com/question/15175106

6 0
3 years ago
Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. T
raketka [301]

Answer:

ΔL =0. 000312  m

Explanation:

Given that

At  room temperature ( T = 25 ∘C)  ,L= 1 m

L=1+2.4\times 10^{-5}T

So the length at  13.0 ∘C above room temperature

L=1+2.4\times 10^{-5}T

L=1+2.4\times 10^{-5}\times 13

L=1.000312 m

So the change in length

ΔL = 1.000312 - 1.0000 m

ΔL =0. 000312  m

4 0
3 years ago
30 points answer ASAP please
djverab [1.8K]

Explanation:

Momentum of the system is a constant when there aren't external forces..

So,When first Balls velocity is went down to zero... its momentum is also zero and beacause momentum should be a constant...now second ball must have a momentum of 20 kg * m/s

4 0
3 years ago
Which factor does notaffect the resistance of a material?
Leona [35]

Answer:

I think c is correct options....

Explanation:

The resistance of the wire increases with increase in temperature. The resistance does not depend on the weight of the wire. Therefore, the correct option is weight.

6 0
3 years ago
Read 2 more answers
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