The work done when a spring is stretched from 0 to 40cm is 4J.
What is work done?
Work done is the magnitude of force multiplied by displacement of an object. It is also the amount of energy transferred to an object when work is done on that.
The work done on the spring to stretch to 40cm is,
F = kx
where F is force, k is force constant.
k = F / x = 10 N / 20 * 10^-2 m = 50 N/m
W = 0.5 * k * (x)^2
where W = work done, k = force constant.
W = 0.5 x 50 x (40 x 10^-2)^2 = 4 J.
Therefore, the work done on the spring when it is stretched to 40cm is 4J.
To learn more about work done click on the given link brainly.com/question/25573309
#SPJ4
Answer:
i. + 22.5 m ii. 4.0 m
Explanation:
i. Image distance
Using the lens formula
1/u + 1/v = 1/f where f = focal length = + 18.0 m, u = object distance = distance of shark away from lens = + 90.0 m and v = image distance from lens = unknown
So, we find v
1/v = 1/f - 1/u
= 1/+18 - 1/+90
= (5 - 1)/90
= 4/90
v = 90/4
= + 22.5 m
So the image is real and formed 22.5 m away on the other side of the lens.
ii Length of Shark
Using the magnification formula, m = image height/object height = image distance/object distance. image height = 1.0 m where object height = length of shark.
m = image distance/object distance
= v/u
= +22.5/+90
= 0.25
0.25 = image height/object height
So,
object height = image height/0.25
= 1.0 m/0.25
= 4.0 m
So, the length of the shark is 4.0 m
I used rise and run to see where point a lies .
That's kind of an answer you could you right?
Answer:
v = 3(m1 - 2m2)/(m1 + m2)
Explanation:
Parameters given:
Velocity of first toy car with mass m1, u1 = 3 m/s (taking the right direction as the positive axis)
Velocity of second toy car with mass m2, u2 = -6 m/s (taking the left direction as the negative x axis)
Using conservation of momentum principle:
Total initial momentum = Total final momentum
m1*u1 + m2*u2 = m1*v1 + m2*v2
Since they stick together after collision, they have the same final velocity.
m1*3 + (m2 * -6) = m1*v + m2*v
3m1 - 6m2 = (m1 + m2)v
v = (3m1 - 6m2) / (m1 + m2)
v = 3(m1 - 2m2) / (m1 + m2)
Answer:
Ok so there are many ways to go at this.
you can get a zip lock bag and put a bunch of plastic around the egg inside the bag. (image down below)
Just anything to slow down the descent speed.
Cushion the egg so that something other than the egg itself absorbs the impact of landing.
Explanation:
