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3 years ago

7

YALL THIS QUESTION IS DUE IN 2 HOURS AND I HAVE 3 MORE PAGED TO DO PLEASE HELP ME WITH THIS PHYSICS HOMEWORK PROBLEM!!!! I ATTAC

HED A PIC OF THE PROBLEM BELOW!!!!

1 answer:

goldfiish [28.3K]3 years ago

7 0

Answer:

I dont know :)

Explanation:

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What would happened if there is no invented of machine?

yuradex [85]

if there were no invention of machines then life would have been more difficult and simple works could be hard to do. Even now we are using our phones, sitting in a AC room interacting to eachother from different places. without the invention of machines simple things like transportation would have been difficult. There would be horses and donkey for the transportation. There would be no electricity,no internet, no transportation, not even c computers or mobile etc. The market for business will be smaller, the knowledge and news about world would be less.

so the problem would have been bigger than we can imagine. But one thing is that nature could survive lot more compared to what we have done till now by destroying nature.

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2 years ago

If a 4.0Ω resistor, a 6.0Ω resistor, and an 8.0Ω resistor are connected in parallel across a 12 volt battery, what is the total

allsm [11]

Answer:

Explanation:

6.7 amps

7 0

3 years ago

Q) A farmer moves along the boundary of a

Alja [10]

The answer will be 8 because kedks

4 0

3 years ago

Calculate the speed for a car that went a distance of 125 meters in 2 seconds time.

stiv31 [10]

Answer:

<h2>62.5 m/s</h2>

Explanation:

The speed of the car can be found by using the formula

$s = \frac{d}{t} \\$

d is the distance

t is the time

From the question we have

$s = \frac{125}{2} = 62.5 \\$

We have the final answer as

<h3>62.5 m/s</h3>

Hope this helps you

5 0

2 years ago

A 500 kg sack of coal falls vertically onto a 2000 kg railroad flatcar which was initially moving horizontally at 3 m/s. no exte

Zinaida [17]

Since there are no external forces, including friction, act on the flatcar. after the sack rests on the flatcar, we would assume that momentum is conserved. This means that

total momentum of car before collision = total momentum of car after collision.

Recall,

momentum = mass x velocity

From the information given,

mass of car before collision = 2000

velocity of car before collision = 3

Thus,

total momentum of car before collision = 2000 x 3 = 6000

Also,

mass of sack = 500

mass of car and sack after collision = 500 + 2000 = 2500

velocity after collision = v

momentum after collision = 2500 x v = 2500v

Since momentum is conserved, then

6000 = 2500v

v = 6000/2500

v = 2.4

the speed of the flatcar is 2.4 m/s

6 0

1 year ago