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Nezavi [6.7K]
3 years ago
14

Help plsssss ..........

Physics
1 answer:
Sholpan [36]3 years ago
4 0

Answer:1. c 2.b

Explanation:

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Which of the following is a consequence of the special theory of relativity?
aleksandr82 [10.1K]

Answer:

D.

Explanation:

Specifically, Special Relativity showed us that space and time are not independent of one another but can be mixed into each other and therefore must be considered as the same object, which we shall denote as space-time. The consequences of space/time mixing are: time dilation. and length contraction.

3 0
2 years ago
A uniform ladder of length L and weight w is leaning against a vertical wall. The coefficient of static friction between the lad
pantera1 [17]

Answer: 45.3°

Explanation:

Given,

Length of ladder = l

Weight of ladder = w

Coefficient of friction = μs = 0.495

Smallest angle the ladder makes = θ

If we assume the forces in the vertical direction to be N1, and the forces in the horizontal direction to be N2, then,

N1 = mg and

N2 = μmg

Moment at a point A in the clockwise direction is

N2 Lsinθ - mg.(L/2).cosθ = 0

μmgLsinθ - mg.(L/2).cosθ = 0

μmgLsinθ = mg.(L/2).cosθ

μsinθ = cosθ/2

sin θ / cos θ = 1 / 2μ

Tan θ = 1 / 2μ

Substituting the value of μ = 0.495, we have

Tan θ = 1 / 2 * 0.495

Tan θ = 1 / 0.99

Tan θ = 1.01

θ = tan^-1(1.01)

θ = 45.3°

3 0
3 years ago
In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separatio
asambeis [7]

Answer:

Δx = 2.5 x 10⁻³ m = 2.5 mm

Explanation:

The distance between two consecutive fringes, also known as fringe spacing, in Young's Double Slit Experiment, is given as follows:

Δx = λL/d

where,

Δx = distance between consecutive fringes = ?

λ = wavelength of light = 500 nm = 5 x 10⁻⁷ m

L = Distance between slits and screen = 5 m

d = slit separation = 1 mm = 1 x 10⁻³ m

Therefore,

Δx = (5 x 10⁻⁷ m)(5 m)/(1 x 10⁻³ m)

<u>Δx = 2.5 x 10⁻³ m = 2.5 mm</u>

4 0
3 years ago
A 2,000 kg rocket is launched 12 km straight up at a constant acceleration into the sky at which point the rocket is travelling
iogann1982 [59]

Answer:

797700000 J

Explanation:

From the question,

The work done by the rocket, is given as,

W = Ek+Ep............. Equation 1

Where Ek and Ep are the potential and the kinetic energy of the rocket respectively.

Ep = mgh............ Equation 2

Ek = 1/2mv²............. equation 3

Substitute equation 2 and equation 3 into equation 1

W = mgh+1/2mv².............. Equation 4

Where m = mass of the rocket, h = height, v = velocity of the rocket, g = acceleration due to gravity.

Given: m = 2000 kg, h = 12 km = 12000 m, v = 750 m/s, g = 9.8 m/s²

Substitute into equation 4

W = 2000(12000)(9.8)+1/2(2000)(750²)

W = 235200000+562500000

W = 797700000 J

6 0
3 years ago
The star aldebaran is a red giant, and is much more luminous than the sun. what conclusions can be drawn from this fact?
Andreyy89
<span>Aldebaran is cooler than the sun but has a larger diameter than the Sun.</span>
5 0
4 years ago
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