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Makovka662 [10]

Answer:

i don't do sports

Explanation:

6 0

3 years ago

A gyroscope flywheel of radius 1.96 cm is accelerated from rest at 13.0 rad/s2 until its angular speed is 2270 rev/min. (a) What

nika2105 [10]

Tangential acceleration of a point on the rim of the flywheel during this spin-up process is 0.2548 m/s².

Tangential acceleration is defined as the rate of change of tangential velocity of the matter in the circular path.

Given,

Radius of flywheel (r) = 1.96 cm = 0.0196m

Angular acceleration (α)= 13.0 rad/s²

The tangential acceleration formula is at=rα

where, α is the angular acceleration, and r is the radius of the circle.

using the formula; at=rα = (13.0 rad/s²) (0.0196m) = 0.2548 m/s².

The tangential acceleration is 0.2548 m/s².

Learn more about the Tangential acceleration with the help of the following link:

brainly.com/question/15743294

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5 0

2 years ago

If you wanted to find a sample of fermium, which has an atomic number of 100, where would you look?

Umnica [9.8K]

Answer:

B

Explanation:

Fermium is a synthetic element with the symbol Fm and atomic number 100. It is an actinide and the heaviest element that can be formed by neutron bombardment of lighter elements, and hence the last element that can be prepared in macroscopic quantities, although pure fermium metal has not yet been prepared.[3] A total of 19 isotopes are known, with 257Fm being the longest-lived with a half-life of 100.5 days.

It was discovered in the debris of the first hydrogen bomb explosion in 1952, and named after Enrico Fermi, one of the pioneers of nuclear physics. Its chemistry is typical for the late actinides, with a preponderance of the +3 oxidation state but also an accessible +2 oxidation state. Owing to the small amounts of produced fermium and all of its isotopes having relatively short half-lives, there are currently no uses for it outside basic scientific research.

5 0

3 years ago

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To practice problem-solving strategy 9.1 a strategy for conservation of momentum problems. an 80-kg quarterback jumps straight u

kherson [118]

Refer to the diagram shown below.

By definition momentum = mass * velocity.

Before throwing the ball:
The initial momentum is
P₁ = 0.

After throwing the ball:
Let u = the backward velocity of the quarterback.
The momentum is
P₂ = (0.43 kg)*(15 m/s) + (80 kg)*(- u m/s)

Conservation of momentum requires that
P₂ = P₁
6.45 - 80u = 0
u = 6.45/80 = 0.0806 m/s

Answer: 0.08 m/s backward

6 0

3 years ago

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2. A hydraulic lift is used to lift heavy machine pushing down on a 5 square meters piston with a force of 1000 N. What force ne

IRINA_888 [86]

Answer:

The force needs to be applied on the 1 square meter piston to lift the machine is 200 N.

Explanation:

Given that,

Force, $F_1=1000\ N$

Area, $A_1=5\ m^2$

We need to find the force needs to be applied on the 1 square meter piston to lift the machine. We know that the pressure at every point is same due to Pascal's law such that :

$P_1=P_2\\\\\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\\dfrac{1000}{5}=\dfrac{F_2}{1}\\\\F_2=200\ N$

So, the force needs to be applied on the 1 square meter piston to lift the machine is 200 N. Hence, this is the required solution.

3 0

4 years ago

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