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3 years ago

For any given wave energy is most related to the __________ of the wave.

Physics

2 answers:

galina1969 [7]3 years ago

3 0

B would be your answer.

k0ka [10]3 years ago

3 0

Intensity of wave is defined as

$I = KA^2$

here K = constant

A = amplitude

we can defined intensity by energy per unit area per unit time

So intensity is given by formula

$I = \frac{Energy}{Area*time}$

So here we can say if` medium properties like density is uniform as well as frequency of wave will not change then energy of wave depends on intensity and intensity of wave directly depends on amplitude

So answer for the above question is Amplitude

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Predict the products of the combustion of methanol, CH3OH(l).

gregori [183]

Answer:

Carbon dioxide and water

Explanation:

The products of complete combustion are always carbon dioxide and water.

The balanced reaction is:

4 CH₃OH + 3 O₂ → 4 CO₂ + 2 H₂O

8 0

3 years ago

Read 2 more answers

A 30.0-kg girl in a swing is pushed to one side and held at rest by a horizontal force \vec{F} F ⃗ so that the swing ropes

Virty [35]

Answer:

169.74 N

Explanation:

Given,

Mass of the girl = 30 Kg

angle of the rope with vertical, θ = 30°

equating the vertical component of the tension

vertical component of the tension is equal to the weight of the girl.

T cos θ = m g

T cos 30° = 30 x 9.8

T = 339.48 N

Tension on the two ropes is equal to 339.48 N

Tension in each of the rope = T/2

= 339.48/2 = 169.74 N

Hence, the tension in each of the rope is equal to 169.74 N

7 0

3 years ago

On earth, two parts of a space probe weigh 14500 N and 4800 N. These parts are separated by a center-to-center distance of 18 m

Nastasia [14]

Answer:

$F = 1.489*10^{-7} N$

Explanation: Weight of space probes on earth is given by: $W= m*g$

W= weight of the object( in N)

m= mass of the object (in kg)

g=acceleration due to gravity(9.81 $\frac{m}{s^{2} }$ )

Therefore,

$m_{1} = \frac{14500}{9.81}$

$m_{1} = 1478.08 kg$

Similarly,

$m_{2} = \frac{4800}{9.81}$

$m_{2} = 489.29 kg$

Now, considering these two parts as uniform spherical objects

Also, according to Superposition principle, gravitational net force experienced by an object is sum of all individual forces on the object.

Force between these two objects is given by:

$F = \frac{Gm_{1} m_{2}}{R^{2} }$

G= gravitational constant ( $6.67 * 10^{-11} m^{3} kg^{-1} s^{-2}$ )

$m_{1} , m_{2}$ = masses of the object

R= distance between their centres (in m)(18 m)

Substituiting all these values into the above formula

$F = 1.489*10^{-7} N$

This is the magnitude of force experienced by each part in the direction towards the other part, i.e the gravitational force is attractive in nature.

7 0

3 years ago

1.- An elevator is being lowered at a constant speed by a steel cable attached to an electric motor. Which statement is correct?

Nady [450]

Answer:

the correct one is C

Explanation:

For this exercise we must use the work definition

W = F. s

Where the bold characters indicate vectors and the point is the scalar producer

W = F s cos θ

Where θ is the angles between force and displacement.

Let us support this in our case. The cable creates an upward tension and with the elevator going down the angle between them is 180º so the work of the cable on the elevator is negative.

The evade has a downward force, its weight so the force goes down and the displacement goes down, as both are in the same direction the work is positive

When examining the statements the correct one is C

4 0

3 years ago

In some employment situations, not all personnel can immediately evacuate a work area per the EAP. It may be that some equipment

Semmy [17]

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3 0

4 years ago