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3 years ago

how does the charge of a particle affect the direction in which the particle is deflected in a magnetic field?

1 answer:

3 0

<span>Negatively charged particles will go toward the positive end of the magnetic field and positively charged particles will go toward the negative end... for two reasons, because the positive is both repelled by the positive part of the field, and its also attracted by the negative end. oh, and on diagrams, the arrows of magnetic flux usually go from negative to positive.

Hope this helps(:</span>

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Buoyant force acts in the opposite direction as the force of

Natalka [10]

Buoyant force acts in the opposite direction as the force of

Gravity

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3 years ago

1. How much force would you have to apply to a 15kg object in order to accelerate it!<br> a 2 m/s?

mihalych1998 [28]

30N

Explanation:

Given parameters:

Mass of object = 15kg

Acceleration = 2m/s

Unknown:

Force = ?

Solution:

Force is given as the product of mass and acceleration:

F = m x a

m is the mass

a is the acceleration

Inputting the parameters:

F = 15 x 2 = 30N

The unit of force is newtons, N .

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3 years ago

you want to compare brands of paper towels to see which holds the most liquid. the independent variable in your experiment would

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Answer: the brand of paper towel

Explanation: the independent variable is the one you control in an experiment. the dependent variable would be the amount of water in the paper towel

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3 years ago

How do you calculate acceleration?

ELEN [110]

Change in velocity per time

7 0

3 years ago

Read 2 more answers

A 2-kg cart, traveling on a horizontal air track with a speed of 3m/s, collides with a stationary 4-kg cart. The carts stick tog

ladessa [460]

Answer:

The impulse exerted by one cart on the other has a magnitude of 4 N.s.

Explanation:

Given;

mass of the first cart, m₁ = 2 kg

initial speed of the first car, u₁ = 3 m/s

mass of the second cart, m₂ = 4 kg

initial speed of the second cart, u₂ = 0

Let the final speed of both carts = v, since they stick together after collision.

Apply the principle of conservation of momentum to determine v

m₁u₁ + m₂u₂ = v(m₁ + m₂)

2 x 3 + 0 = v(2 + 4)

6 = 6v

v = 1 m/s

Impulse is given by;

I = ft = mΔv = m(

The impulse exerted by the first cart on the second cart is given;

I = 2 (3 -1 )

I = 4 N.s

The impulse exerted by the second cart on the first cart is given;

I = 4(0-1)

I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).

Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.

8 0

4 years ago