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Trava [24]
3 years ago
11

I'm in dire need of some help, The first correct response receives brainlest!

Physics
2 answers:
tia_tia [17]3 years ago
8 0
C. They both hit at the same time
tino4ka555 [31]3 years ago
7 0

If they're dropped from the same height at the same time and there's no air resistance, the the lighter ball and the heavier ball, as well as a feather, a hammer, a bowling ball, a speck of dust, a school bus, and a battle ship, will all fall side-by-side and hit the ground at the same time.  

We've known this for about 400 years, since Galileo.  And we've known WHY for about 300 years, since Newton.

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A group of engineers is preparing a satellite to land by moving it 10% closer to
aleksklad [387]

Answer:

Rotational inertia decreases proportional to the decrease in the radius of rotation.

Explanation:

7 0
3 years ago
A uniform-density sphere whose mass is 13 kg and radius is 0.3 m
geniusboy [140]

What are you trying to find?


6 0
3 years ago
1.
Brilliant_brown [7]

Answer:

1) solvent

2) liquid-solid

3) gas - gas

Explanation:

1) A solution is the homogenous mixture of two or more substances in such a way that its components are uniformly distributed. In any solution, the solvent make up the greatest quantity or volume while the solute is of lesser quantity.

2) liquid-solid is the most common type of solution.

3) A gas solution can be a gas dissolved in a gas, or a liquid dissolved in a gas, or a solid dissolved in a gas.  Air is a gas - gas solution, it is composed of oxygen and other dissolved gases in nitrogen

6 0
3 years ago
A particle's position is given by z(t) = −(6.50 m/s2)t2k for t ≥ 0. (Express your answer in vector form.) a. Find the particle's
blondinia [14]

Answer:

a) z'(t) =v(t) = -13t

Now we can replace the velocity for t=1.75 s

v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}

For t = 3.0 s we have:

v(3.0s) = -13*3.0 =-39 \frac{m}{s}

b) v_{avg}= \frac{z_f - z_i}{t_f -t_i}

And we can find the positions for the two times required like this:

z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m

z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m

And now we can replace and we got:

V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}

Explanation:

The particle position is given by:

z(t) = -(6.5 \frac{m}{s^2}) t^2, t\geq 0

Part a

In order to find the velocity we need to take the first derivate for the position function like this:

z'(t) =v(t) = -13t

Now we can replace the velocity for t=1.75 s

v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}

For t = 3.0 s we have:

v(3.0s) = -13*3.0 =-39 \frac{m}{s}

Part b

For this case we can find the average velocity with the following formula:

v_{avg}= \frac{z_f - z_i}{t_f -t_i}

And we can find the positions for the two times required like this:

z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m

z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m

And now we can replace and we got:

V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}

8 0
3 years ago
If the amplitude of a wave is doubled, it has half the velocity.<br><br> TRUE or FALSE?
blondinia [14]

Answer:

true

Explanation:

7 0
4 years ago
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