1. Jumping off a building
2. Hitting a tennis ball
3. Swinging a bucket of water in a circle
Answer:
35.489km
Explanation:
a diagram illustrating the question is attached
now, applying cosine rule to find the displacement c
cosine rule;
c²=a²+b²-2abCos ∅
c²=50²+80²-2(50)(80)Cos 38°
c²=2500 + 6400 - (8000×0.9951)
c²=8900-7640.589
c²=1259.411
c=
c=35.49km
They both move in the opposite direction in which they hit
Answer:
The box displacement after 6 seconds is 66 meters.
Explanation:
Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (
), in meters, can be determined by the following expression:
(1)
Where:
- Initial velocity, in meters per second.
- Time, in seconds.
- Acceleration, in meters per square second.
If we know that
,
and
, then the box displacement after 6 seconds is:

The box displacement after 6 seconds is 66 meters.
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