Determine the volume of the figure. Round you answer to the nearest tenth of a cubic foot.

Write an expression that represents the volume of a rectangular-shaped box with a length 3 inches less than its height and a wid

AfilCa [17]

The expression that represents the volume of a rectangular-shaped box is: A. x³ + x² - 12x.

<h3>What is the Volume of a Rectangular Prism?</h3>

A rectangular-shaped box is a rectangular prism. To find the volume of a rectangular-shaped box, we would apply the formula of the volume of a rectangular prism, which is expressed as: V = (length)(width)(height).

We are given the following dimensions of the rectangular-shaped box:

Let the height be represented as x

Height of the rectangular-shaped box = x in.

Length of the rectangular-shaped box = (x - 3) in.

Width of the rectangular-shaped box = (x + 4) in.

Plug in the values into the volume formula:

Volume of the rectangular-shaped box = (x - 3)(x)(x + 4)

Expand (x - 3)(x)(x + 4)

Volume of the rectangular-shaped box = x³ + x² - 12x.

Therefore, the expression that represents the volume of a rectangular-shaped box with the given dimensions is: A. x³ + x² - 12x.

Learn more about the volume of rectangular prism on:

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5 0

1 year ago

The total cost for 8 bracelets, including shipping was $54. The shipping charge was $6. Define your variable and write an equati

Alenkasestr [34]

8x+6=54
    -6   -6
    8x=48
8x /8=48/8
      x=6 the bracelets were $6 a piece

5 0

3 years ago

Read 2 more answers

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

3 years ago

I NEEF HELP GO FIND MY QUESTION PLSSSS

torisob [31]

What’s your question ?

4 0

3 years ago

Read 2 more answers

I have like five of these so I'm sorry.

myrzilka [38]

Answer:

z ≥ -5/6