Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130

BD is 18
XY is 4
IK is 8
DF is 16
Answer:
4(7y-8)
Step-by-step explanation:
9514 1404 393
Answer:
100°
Step-by-step explanation:
Arc BC is twice the measure of inscribed angle BEC, so is ...
arc BC = 2×50°
arc BC = 100°
Answer:
Simplify.
(2x2 - 5x + 3) - (-x2 + 4x - 5)
the answer is -7x +12
Step-by-step explanation:
the question can be solved using BODMAS law
from Simplify.
(2x2 - 5x + 3) - (-x2 + 4x - 5)
opening the bracket
4-5x + 3 + 2x - 4x + 5
collecting the like terms we have;
12-7x
therfore ; -7x + 12